Answer : The concentration of and at equilibrium is, 0.0158 M and 0.00302 M respectively.
Explanation :
First we have to calculate the concentration of
Now we have to calculate the value of equilibrium constant (K).
The given chemical reaction is:
Initial conc. 0.0163 0.00415 0.00276
At eqm. (0.0163-2x) (0.00415+x) (0.00276+x)
As we are given:
Concentration of at equilibrium = 0.00467 M
That means,
(0.00415+x) = 0.00467
x = 0.00026 M
Concentration of at equilibrium = (0.0163-2x) = (0.0163-2(0.00026)) = 0.0158 M
Concentration of at equilibrium = (0.00276+x) = (0.00276+0.00026) = 0.00302 M
Electronegativity is defined as the extent at which an atom can attract the bonding pair of another in a couvalent bond
fluorine has the highest electronegativity so away from it electonegativity decrease so the answer would be nitrogen as its the closes plus it has a strong nuclear charge with a small radius
hope that helps
Answer: The answer is 726 cg
Explanation:
The chart is attached below and the options are as follow,
A Benzene
B Methanol
C Hexane
D Octane
Answer: Option-B (Methanol) is the correct answer.
Explanation: As we know that the substance given to student is soluble in water. Therefore, those substances which are soluble in water are
polar in nature because water is
polar in nature and
Like Dissolves Like.
Hence, in chart it can easily be seen that
Methanol is also polar in nature due to presence of -O-H (polar) bond. So, the substance will dissolve in it.
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