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mr_godi [17]
3 years ago
9

Sketch the graph of each line: 6y-y=1

Mathematics
1 answer:
jeyben [28]3 years ago
8 0
Go to this website called papa math it will help you with graphs

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Simplify the expression -2+6.45z-6+(-3.25z)
erik [133]

Answer:

-8 + 3.2z

Step-by-step explanation:

  1. when there is a "+" in front of an expression in parentheses, the expression remains the same
  2. -2 + 6.45z - 6 - 3.25z
  3. calculate the difference

-8 + 6.45z - 3.25z

collect like terms

-8 + 3.2z

8 0
3 years ago
What is the size of the matrix resulting from
kogti [31]

Answer:

1×3 or 3×3 I think...........

7 0
3 years ago
Read 2 more answers
-3x + 4y = 12<br> 3x – 6y = 18<br> Answer has to be (x,y)
navik [9.2K]

Answer:

(24, -15)

Step-by-step explanation:

-3x + 4y = 12

3x – 6y = 18

Add the two equations together to first solve for y

-2y=30

y=-15

Enter -15 into one of the equations to solve for x

-3x + 4(-15) = 12

-3x-60=12

-3x=72

x=24

Hope this helps! Please mark brainliest :)

4 0
4 years ago
Use properties of limits and algebraic methods to find the limit, if it exists. (If the limit is infinite, enter '[infinity]' or
soldi70 [24.7K]

Answer:

The limit of this function does not exist.

Step-by-step explanation:

\lim_{x \to 3} f(x)

f(x)=\left \{ {{9-3x} \quad if \>{x \>< \>3} \atop {x^{2}-x }\quad if \>{x\ \geq \>3 }} \right.

To find the limit of this function you always need to evaluate the one-sided limits. In mathematical language the limit exists if

\lim_{x \to a^{-}} f(x) = \lim_{x \to a^{+}} f(x) =L

and the limit does not exist if

\lim_{x \to a^{-}} f(x) \neq \lim_{x \to a^{+}} f(x)

Evaluate the one-sided limits.

The left-hand limit

\lim_{x \to 3^{-} } 9-3x= \lim_{x \to 3^{-} } 9-3*3=0

The right-hand limit

\lim_{x \to 3^{+} } x^{2} -x= \lim_{x \to 3^{+} } 3^{2}-3 =6

Because the limits are not the same the limit does not exist.

8 0
4 years ago
Find the markup and the cost of the following item. Round answers to the nearest cent.
marysya [2.9K]

Answer:

1st question: M=22.62 while C=75.38

2nd question: M=.22 while C=1.97

Step-by-step explanation:

If a mirror costing x dollars is marked up 30%, then we have to find x such that 30%x+x is 98 dollars.

We are solving:

.3x+x=98

Combine like terms:

1.3x=98

Divide both sides by 1.3:

x=75.38

M=98-75.38=22.62

C=75.38

So M=22.62 while C=75.38.

If ream of paper cost x and is marked up 11%, then we have to find x such that 11%x+x is 2.19.

We are solving:

.11x+x=2.19

1.11x=2.19

x=1 97

M=2.19-1.97=.22

So M=.22 while C=1.97

5 0
4 years ago
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