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Sholpan [36]
3 years ago
5

which of the following describes something an engineer would probably do first when developing new technology meant to reduce oc

ean pollution

Chemistry
1 answer:
JulijaS [17]3 years ago
3 0

Answer:

Option B. is the right answer.

Explanation:

Before developing a new technology, an engineer has to evaluate the advantages and disadvantages of the chemical used in order to clean water bodies. If the chemical has more disadvantages as compared to advantages, so its usage will be avoided while if the chemical does not harm the marine organisms of the ocean so it can be used for the purpose of cleaning. So we can say that first the engineer has to study the chemicals.

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Which is the strongest base among NO3-, So4-, CH3COO- and Cl-​
vodomira [7]

Answer:

CH3COO-

Explanation:

The conjugate base if a weak acid is a strong base, and the conjugate base of a strong acid is a weak base.

Acetic acid is a weak acid, so its conjugate base (CH3COO-) is a strong base.

Nitric, sulfuric, and hydrochloric acids are all strong acid. Their conjugate bases (NO3-, SO4^2-, and Cl- are all weak bases.

3 0
3 years ago
Which of these are broken down during chemical,but not physical,changes
KIM [24]

Which of these what?

This isn't clear, can you put the answer choice or something?

7 0
3 years ago
HNO3 + H2O > H3O(aq) + NO3-(aq)
Kruka [31]
What is the question and are there answers to go with it
8 0
4 years ago
Given that the initial rate constant is 0.0110s−1 at an initial temperature of 21 ∘C , what would the rate constant be at a temp
gulaghasi [49]

The rate constant is mathematically given as

K2=2.67sec^{-1}

<h3>What is the Arrhenius equation?</h3>

The rate constant for a particular reaction may be calculated with the use of the Arrhenius equation. This constant can be stated in terms of two distinct temperatures, T1 and T2, as follows:

ln(\frac{K2}{K1})= (\frac{Ea}{R})*(\frac{1}{T1}-\frac{1}{T2})

Therefore

KT1= 0.0110^{-1}

T1= 21+273.15

T1= 294.15K

T2= 200  

T2=200+273.15

T2= 473.15K

Ea= 35.5 Kj/Mol

Hence, in  j/mol R Ea is

Ea=35.5*1000 j/mol R

ln(\frac{K2}{0.0110})= (\frac{35.5*1000}{8.314})*(\frac{1}{294.15}-\frac{1}{473.15}\\\\ln(\frac{K2}{0.0110})=5.492

K2/0.0110 =e^(5.492)

K2/0.0110 =242.74

K2= 242.74*0.0110

K2=2.67sec^{-1}

In conclusion, rate constant

K2=2.67sec^{-1}

Read more about rate constant

brainly.com/question/20305871

#SPJ1

5 0
2 years ago
Answer as many as you can please, 40 POINTS
ICE Princess25 [194]
It would be to see your awnsers

6 0
3 years ago
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