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Nat2105 [25]
3 years ago
7

What will mostly happen if two bromine atoms bond toghether

Chemistry
2 answers:
zepelin [54]3 years ago
8 0
A covalent bond will hold them together..
Brilliant_brown [7]3 years ago
6 0
An ionic bond will hold them together
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The number of atoms present in 2.5 mole of triatomic gas is equivalent to ​
RUDIKE [14]

Answer: 1.41725 X 10^{24} atoms

Explanation:

One male of any gas containing no. of atoms$=6.023\times10^{23}$

2.5 moles of gas containing no. of atoms$=2.5\times6.023\times10^{23}$$=15.0575\times10^{23}$

The given gas is triatomic gas. Hence

No. of atoms$=3\times15.075\times10^{23}$

$=14.1725\times10^{23}$\\$=1.41725\times10^{24}$

6 0
3 years ago
Which environmental changes occur fastest? oil spill changing seasons global warming pond succession Previous hurry plzz
ser-zykov [4K]
I’m not a 100% shure but I would personally say OIL SPILLS.
6 0
3 years ago
Which type of system must exist for chemical equilibrium
larisa86 [58]

Answer: closed system.

Explanation:

4 0
3 years ago
How many liters of carbon dioxide will be produced at STP if 3.56 g calcium carbonate reacts completely with carbon dioxide? CaC
sp2606 [1]

Answer:

V = 0.798 L

Explanation:

Hello there!

In this case, for this gas stoichiometry problem, we first need to compute the moles of carbon dioxide via stoichiometry and the molar mass of starting calcium carbonate:

3.56gCaCO_3*\frac{1molCaCO_3}{100gCaCO_3} *\frac{1molCO_2}{1molCaCO_3} =0.0356molCO_2

Next, we use the ideal gas equation for computing the volume, by bearing to mind that the STP conditions stand for a pressure of 1 atm and a temperature of 273.15 K:

PV=nRT\\\\V=\frac{nRT}{P}\\\\V=\frac{0.0356mol*0.08206\frac{atm*L}{mol*K}*273.15K}{1atm} \\\\V=0.798L

Best regards!

4 0
3 years ago
What volume in mt, of 0.5a M1HCI solution is needed to neutralize 77 ml of 1.54 M NaOH solution?
Rainbow [258]

Answer:

237.2 mL.

Explanation:

  • We have the rule: at neutralization, the no. of millimoles of acid is equal to the no. of millimoles of the base.

(XMV) acid = (XMV) base.

where, X is the no. of (H) or (OH) reproducible in acid or base, respectively.

M is the molarity of the acid or base.

V is the volume of the acid or base.

<em>(XMV) HCl = (XMV) NaOH.</em>

<em></em>

For HCl; X = 1, M = 0.5 M, V = ??? mL.

For NaOH, X = 1, M = 1.54 M, V = 77.0 mL.

<em>∴ V of HCl = (XMV) NaOH / (XV) HCl = (</em>1)(1.54 M)(77.0 mL) / (1)(0.5 M) = <em>237.2 mL.</em>

8 0
3 years ago
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