The order of the students from the most reliable to the least reliable is C. Student 4, Student 1, Student 2, Student 3.
<h3>what student has the most reliable data?</h3><h3 />
the student with the most reliable data is the one that has the least variation in their data in the various trials.
this student is therefore student 4.
the next student would be student 1 and student 2 would be the third most reliable.
student 3 has large variations in their trials which makes their data the least reliable.
find out more on reliable data at brainly.com/question/8391667.
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Then, at a critical point during interphase (called the S phase), the cell duplicates its chromosomes and ensures its systems are ready for cell division. If all conditions are ideal, the cell is now ready to move into the first phase of mitosis.
Answer:
The answer to your question is 203.8 g
Explanation:
Data
Average atomic mass = ?
Centium-200
Centium-203
Centium-209
Equal amounts
Process
1.- Determine the abundance of each isotope.
If they are in equal amounts in nature, just divide 100 by 3
100/3 = 33.33 % or 0.333
2.- Determine the Average atomic mass
Average atomic mass = Atomic mass 1 x abundance + Atomic mass 2 x
abundance + Atomic mass 3 x abundance
- Substitution
Average atomic mass = 200 x 0.333 + 203 x 0.333 + 209 x 0.333
- Simplification
Average atomic mass = 66.6 + 67.6 + 69.6
Result
Average atomic mass = 203.8 g
