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Arada [10]
3 years ago
10

What evidence supports Bohr’s claim that an electron is found only in specific energy levels around the nucleus of the atom. And

then connect this evidence to the claim through reasoning
Chemistry
2 answers:
Alex Ar [27]3 years ago
6 0

Energy Levels of Electrons. As you may remember from chemistry, an atom consists of electrons orbiting around a nucleus. ... They are restricted to orbits with only certain energies. Electrons can jump from one energy level to another, but they can never have orbits with energies other than the allowed energy levels.



Lorico [155]3 years ago
4 0

Energy Levels of Electrons. As you may remember from chemistry, an atom consists of electrons orbiting around a nucleus. ... They are restricted to orbits with only certain energies. Electrons can jump from one energy level to another, but they can never have orbits with energies other than the allowed energy levels.

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How many liters of 1.2M solution can be prepared with 0.50 moles of C6H12O6
BigorU [14]
First you need to know the molecular weight of sugar (C6H12O6) which is 180.156g/mol
You have half a mole so you have 90.078g
If you wanted to make 1L of a 1.2M solution of glucose you would need 180.156*1.2=216.1872g
But you only have 90.078g
So you need to figure out how much this 90.078g will make if the solution must be 1.2M:
90.078g/216.1872g=xL/1L
solve for the X and you get 0.416666666...
so 416.7ml or 0.417L
5 0
3 years ago
Which one of the following compounds utilizes both ionic and covalent bonding?A) C6H12O6.B) CC32-.C) CO2.D) MgCl2.E) Al2(SO4)3.
JulsSmile [24]

Answer:

Al2(SO4)3

Explanation:

Looking at this carefully, we will discover that Al2(SO4)3 is composed of Al^3+ and SO4^2-.

The aluminum and sulphate ions are ionically bonded. However, the oxygen and sulphur in the sulphate ion are covalently bonded.

Hence, Al2(SO4)3 contains both ionic and covalent bond.

8 0
3 years ago
Please help if you do the food chain has to have the gray wolf in it
Marat540 [252]

Answer:

grass->bug->mice->wolf

Explanation:

7 0
3 years ago
Read 2 more answers
Four oranges were placed in a series circuit. Approximately what voltage did this produce?
vampirchik [111]

Answer:

Four times the original amount if only one orange was used

Explanation:

We can assume that the oranges all have equal voltages. Connecting them in series will have an increasing effect on the voltage delivered. In our case, this will produce 4 times the voltage of the circuit when only one orange is used.

Whenever simple cells are connected in series, the voltages of the individual cells are added up to form the voltage of the whole circuit.

Let us assume that the voltage of each of the oranges is approximately 0.9 volts. The Voltage produced when the 4 oranges are joined in series is 0.9 + 0.9 + 0.9 + 0.9 = 3.6 volts

3 0
3 years ago
A 0.1326 g sample of magnesium was burned in an oxygen bomb calorimeter. the total heat capacity of the calorimeter plus water w
Sladkaya [172]

Answer: Th enthalpy of combustion for the given reaction is 594.244 kJ/mol

Explanation: Enthalpy of combustion is defined as the decomposition of a substance in the presence of oxygen gas.

W are given a chemical reaction:

Mg(s)+\frac{1}{2}O_2(g)\rightarrow MgO(s)

c=5760J/^oC

\Delta T=0.570^oC

To calculate the enthalpy change, we use the formula:

\Delta H=c\Delta T\\\\\Delta H=5760J/^oC\times 0.570^oC=3283.2J

This is the amount of energy released when 0.1326 grams of sample was burned.

So, energy released when 1 gram of sample was burned is = \frac{3283.2J}{0.1326g}=24760.181J/g

Energy 1 mole of magnesium is being combusted, so to calculate the energy released when 1 mole of magnesium ( that is 24 g/mol of magnesium) is being combusted will be:

\Delta H=24760.181J/g\times 24g/mol\\\\\Delta H=594244.3J/mol\\\\\Delta H=594.244kJ/mol

4 0
3 years ago
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