1.b
2.b
3.a
3 was the the opposite of the scenario stated
<span>Solids, Liquids, Gases, Plasma, and Bose-Einstein Condensates. The main differences between these states of matter are the densities of the particles.</span>
Answer:
18.0 g of mercury (11) oxide decomposes to produce 9.0 grams of mercury
Explanation:
Mercury oxide has molar mass of 216.6 g/ mol. It gas a molecular formula of HgO.
The decomposition of mercury oxide is given by the chemical equation below:
2HgO ----> 2Hg + O₂
2 moles of HgO decomposes to produce 1 mole of Hg
2 moles of HgO has a mass of 433.2 g
433.2 g of HgO produces 216.6 g of Hg
18.0 of HgO will produce 18 × 216.6/433.2 g of Hg = 9.0 g of Hg
Therefore, 18.0 g of mercury (11) oxide decomposes to produce 9.0 grams of mercury
The answer is: C. 0.00427 m.
A) 1 km = 1000000 mm.
d = 0.0000427 km · 1000000 mm/km.
d = 47.7 mm.
B) 1 hm = 100000 mm.
d = 0.000427 hm · 100000 mm/hm.
d = 42.7 mm.
C) 1 m = 1000 mm.
d = 0.00427 m · 1000 mm/m.
d = 4.27 mm.
D) 1 cm = 10 mm.
d = 4.27 cm · 10 mm/cm.
d = 42.7 mm.
Millimeter (abbreviated: mm, a thousandth part of metar) is an unit of distance in the metric system.
The answer is: 27 grams of aluminium.
Balanced chemical reaction: 2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂.
n(H₂) = 1.5 mol; amount of hydrogen.
Form chemical reaction: n(Al) : n(H₂) = 2 : 3.
n(Al) = 2 · 1.5 mol ÷ 3.
n(Al) = 1.0 mol; amount of aluminium.
m(Al) = n(Al) · M(Al).
m(Al) = 1 mol · 27 g/mol.
m(Al) = 27 g; mass of aluminium.
