Let us assume that the density of seawater is similar to
ordinary water that is:
density ρ = 1000 kg / m^3
Then we can calculate the hydraulic pressure using the
formula:
P = ρ g h
P = (1000 kg / m^3) * 9.81 m/s^2 * 9,500 m
<span>P = 93,195,000 Pascal</span>
Answer:
t = 5.2 min
Explanation:
given:
A man walks 2km in 1.5min,
find:
how many time need to walk 6.9km
solution:
its a ratio and proportion
<u> 2 km </u> x <u> 6.9 km </u>
1.5 min t
then cross multiply:
2 (t) = 6.9 ( 1.5)
t = 10.35 / 2
t = 5.2 min
Answer:
a) 10.29° upstream
b) t=338.7s
Explanation:
If the river is 1km wide and the destination point is 0.5km away downstream, then the angle and distance the the boat has to travel is:
The realitve velocity of the boat respect to the water is:
where β is the angle it has to be pointed at.
From the relative mvement equations:
where
From this equation we get one equation per the x-axis and another for the y-axis. If we square each of them and add them together, we will get 2 equations:
Solving for V:
V = 3.3m/s and V=-1.514m/s Replacing this value into one of our previous x or y-axis equations:
The amount of time: