What will happen to the gravitational force between two bodies if the distance between them is halved keeping their masses const
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Answer:
a) t = 2.64s
b) Vf = -28.7m/s
Explanation:
If the balloon is descending, the velocity is -2.3m/s. So the equation to describe the postion of the falling camera is:
Solving for t, we get:
t1 = -3.1s and t2 = 2.64s We discard the negative time and use the positive one.
The velocity of the camera will be:
Vf = Vo - g*t = -2.3 - 10*2.64 = -28.7m/s