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3 years ago

Use technology to solve for x. 2x−8=3x−9 What are the solutions?

Mathematics

1 answer:

deff fn [24]3 years ago

3 0

Step-by-step explanation:

$2x - 8 = 3x - 9 \\ \\ \therefore \: 9 - 8 = 3x - 2x \\ \\ \therefore \: 1 = x \\ \\ \therefore \: x = 1$

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Use a graphing calculator to sketch the graph of the quadratic equation, and then state the domain and range. y = negative 5 x s

KengaRu [80]

Answer:

Use a graphing calc.

Domain: All real numbers

Range: (negative infinity, 10.45]

Step-by-step explanation:

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3 years ago

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Tom is putting cartons of ice-cream in one of the freezers. There are 13 boxes and each box contains 24 cartons. How many carton

Mnenie [13.5K]

24x13=312

There are a total of 312 total ice cream cartons.

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3 years ago

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Travelers who fail to cancel their hotel reservations when they have no intention of showing up are commonly referred to as no-s

notsponge [240]

Answer:

a) 0.0523 = 5.23% probability that at least two of the four selected will turn to be no-shows.

b) 0 is the most likely value for X.

Step-by-step explanation:

For each traveler who made a reservation, there are only two possible outcomes. Either they show up, or they do not. The probability of a traveler showing up is independent of other travelers. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

No-show rate of 10%.

This means that $p = 0.1$

Four travelers who have made hotel reservations in this study.

This means that $n = 4$

a) What is the probability that at least two of the four selected will turn to be no-shows?

This is $P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{4,2}.(0.1)^{2}.(0.9)^{2} = 0.0486$

$P(X = 3) = C_{4,3}.(0.1)^{3}.(0.9)^{1} = 0.0036$

$P(X = 4) = C_{4,4}.(0.1)^{4}.(0.9)^{0} = 0.0001$

$P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4) = 0.0486 + 0.0036 + 0.0001 = 0.0523$

0.0523 = 5.23% probability that at least two of the four selected will turn to be no-shows.

b) What is the most likely value for X?

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{4,0}.(0.1)^{0}.(0.9)^{4} = 0.6561$

$P(X = 1) = C_{4,1}.(0.1)^{1}.(0.9)^{3} = 0.2916$

$P(X = 2) = C_{4,2}.(0.1)^{2}.(0.9)^{2} = 0.0486$

$P(X = 3) = C_{4,3}.(0.1)^{3}.(0.9)^{1} = 0.0036$

$P(X = 4) = C_{4,4}.(0.1)^{4}.(0.9)^{0} = 0.0001$

X = 0 has the highest probability, which means that 0 is the most likely value for X.

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3 years ago

Sam bought some toys. He bought a baseball for $5.88, and paid $8.41

myrzilka [38]

Answer:

$5.71

Step-by-step explanation:

20-5.88=14.12

14.12-8.41=5.71

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A grocery store chain has been tracking data on the number of shoppers that use coupons. The data shows that 71% of all shoppers

sesenic [268]

<span>The computation for the confidence level = (18/20) x 100% = 90 %, the E or the margin error = 0.023 and the p = to 0.71. Confidence interval can be achieved by using the formula (p-E, p+E) = (0.71-0.025, 0.71+0.025). Therefore, the confidence interval is (0.685,0.735).</span>

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