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gayaneshka [121]
2 years ago
6

When paper is burned, the mass of the remaining ash is less than the mass of the original paper.

Chemistry
1 answer:
Semmy [17]2 years ago
6 0

Answer:

Some of the products of the reaction were given off as a gas.

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Calculate sound speed in hydrogen H2 at temperture 50 C degree. Answer give in meter per second.
irina [24]

Answer:

The speed of sound in hydrogen gas is 361.5 ^{\circ} C

Explanation:

It is given that the temperature is 50 ^{\circ} C.

The speed of sound in meter per second is calculated by an equation.

The equation states that speed of the sound in meter per second is equal to the sum of the product of the temperature in degree celsius with 0.60 and a constant that is 331.5.

The equation is written as:

speed \ of \ sound \left(m/s \right) = 0.60 \times T + 331.5

Put the value of T = 50 then the equation becomes,

speed \ of \ sound \left(m/s \right) = 0.60 \times 50 + 331.5

Speed of sound (in m/s) = 361.5 m/s

4 0
3 years ago
Describe the process of making the four major macromolecules.
dybincka [34]

Answer:

<em>Proteins, carbohydrates, nucleic acids, and lipids are the four major classes of biological macromolecules—large molecules necessary for life that are built from smaller organic molecules. Macromolecules are made up of single units known as monomers that are joined by covalent bonds to form larger polymers.</em>

Explanation:

Have a great day!

8 0
2 years ago
Read 2 more answers
Copper (II) oxide can be heated until it decomposes into elemental copper and oxygen gas. Is 0.695 grams of Copper (II) oxide is
insens350 [35]

Answer:

0.55 g of Cu can produced by this decomposition

Explanation:

Let's think the reaction of decomposition:

2CuO → 2Cu + O₂

Ratio is 2:2. 2 moles of CuO can decompose into 2 moles of Cu and 1 mol of oxygen.

Let's convert the mass of oxyde to moles → 0.695 g. 1 mol/ 79.55 g =

8.74×10⁻³ moles

8.74×10⁻³ mol of CuO decompose to 8.74×10⁻³ moles of Cu

Let's find out the mass → 8.74×10⁻³ mol . 63.55 g/1mol = 0.55 g

4 0
3 years ago
Read 2 more answers
A gas mixture contains SO 2 SO2 ( molar mass = 64 g/mol ) (molar mass=64 g/mol) and no other source of sulfur. If the mixture is
Slav-nsk [51]

Answer : The percentage (by mass) of SO_2 in the mixture is 20 %

Explanation :

As we are given that, 10 % sulfur by mass that means 10 grams of sulfur present in 100 grams of mixture.

Mass of sulfur = 10 g

Mass of mixture = 100 g

Now we have to calculate the mass of SO_2.

As, 32 grams of sulfur present in 64 grams of SO_2

So, 10 grams of sulfur present in \frac{10}{32}\times 64=20 grams of SO_2

Thus, the mass of SO_2 is 20 grams.

Now we have to calculate the percentage (by mass) of SO_2 in the mixture.

\% \text{ of }SO_2=\frac{\text{Mass of }SO_2}{\text{Mass of mixture}}\times 100

\% \text{ of }SO_2=\frac{20g}{100g}\times 100=20\%

Therefore, the percentage (by mass) of SO_2 in the mixture is 20 %

4 0
3 years ago
Sulfur dioxide emissions from coal-burning power plants are removed by flue-gas desulfurization. The flue gas passes through a s
irakobra [83]

So they tell us that we have four giggle years of flue gas and they're wanting us to find out how much calcium Sophia in kilograms we can obtain from this. So we know that one Giga Leader is equal to one time 10 to the nine leaders.

and they inform us that our stress is equal to one surroundings and that our temperature is equal to 25 degrees Celsius. i am just gonna add to seventy three Calvin to this. So our temperature goes to be 98. Calvin. All proper, so we are simply gonna plug the whole thing into our equation. So one atmosphere times our quantity so four times, 10 to the nine leaders. we're gonna divide this through ours. i'm just gonna use artwork zero.8 to 1 leader's atmosphere per mole, Kelvin.

and then we are gonna times that by way of our temperature. so to 98 Calvin. All right, so when we calculate this out, are moles of flue gasoline is gonna identical to one.6 35 instances generally tend to the 8 moles of our flue gasoline. So now that we've got our moles of flue gas, we need to find a connection between the most of flue fuel and the mass of our calcium selfie.

So if we pass up here, we see that one more of our silver dioxide is equal to at least one mole of our calcium sulfate. So we're gonna use that connection to help us discover the big calcium selfie. So we want to locate the moles of our sulfur dioxide and they provide us the mole fraction for silver dioxide. they say it's a thousand times that of clean air, and we recognize that the mole fraction for easy air is two instances 10 to the negative 10.

So our mole fraction to be able to is equal to two instances 10 to the poor, 10 times a thousand. So our new mole fraction for S 02 goes to be  instances 10 to the terrible seven. Hurry. And we realize our moles of sulfur dioxide are identical to its mole fraction times the full wide variety of moles. So we do recognise the full variety of moles.

it's what number of moles of our flue gas we have. So our moles of eso to is gonna be too  instances 10 to the negative seven instances 1.635 times tend to the 8 moles. So our moles of sulfur dioxide goes to be 32.7 moulds. So now that we've maximum of the sulfur dioxide, we are able to get the moles of our calcium, Sophie, and that's just gonna be the moles of our sulfur dioxide. And we're gonna times that by means of that one toe, one-mole ratio. So one mole, calcium Sophie to at least one-mole sulfur dioxide.

So the moles of our calcium sulphate is the same at 32.7 maximum. So now, to get the mass of our calcium selfie, we simply take our range of maximum of 32.7 moles. I worked inside the times that via its molar mass, that's 136.14 grams in keeping with mole.

So our mass of calcium sulfate is equal to four hundred or 4451.eight g. They need this in kilograms. Sword goes to divide this by way of hundreds. So when we do this, it is gonna equal 4 factors for 518 kilograms of our calcium. So toes and that is Thea amount or the mass of calcium sulphate we will get from four Giga leaders of flue gasoline.

All right, so for the second a part of this question, they're asking us the quantity of air needed to react with all the calcium sulphides. as a way to figure that out, we're gonna need to parent out the moles of 02 They do give us the mole fraction for 02 and it is identical to 0.2 09 after which we're searching out the quantity of air in leaders. All proper, so we recognize that moles of 02 are identical to its small fraction times the full moles of air So maximum of 02 is gonna be 0 factor 209 times all through moles of air.

So allow's simply use that variety for our Mueller ratio to discern out our moles of calcium sulphate. So we are gonna use 32.7 of our calcium, so fight as it's simply gonna be a 1 to one ratio. Oh, we recognize that for each 1.five moles of 02 we've one mole, our calcium sulfate. and then we also know that for each one mole of air, we've got zero.209 moles of 02 So we calculate this out. Are moles of air goes to same 78.2 moles of air?

So then, to get the volume we are simply gonna use PV is same to N. R. T. So we're solving for quantity. So n r t divided through the pressure. They tell us that the pressure is same to 1 environment and we are gonna be using a temperature equal to 2 98 Calvin.

So our extent is gonna identical 78.2 moles of air while times that through our cost of zero.8 to one leaders surroundings in keeping with greater Calvin or in times that fireplace temperature, which is to ninety eight Calvin, I might not divide all of this through one surroundings. So our extent of air is gonna identical to 1913 leaders of air this is had to react absolutely with calcium sulfate. and that's how we noticed the second part of this problem.

Learn more about calcium sulfate brainly.com/question/7962933

#SPJ4

6 0
1 year ago
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