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gayaneshka [121]
2 years ago
6

When paper is burned, the mass of the remaining ash is less than the mass of the original paper.

Chemistry
1 answer:
Semmy [17]2 years ago
6 0

Answer:

Some of the products of the reaction were given off as a gas.

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What is the mass of an atom with seven protons, seven neutrons, and eight electrons?
belka [17]

Answer:

14

Explanation:

mass number = protons + neutrons

6 0
3 years ago
Muscles work in _____ so when other muscles contract the other ___
abruzzese [7]
The first word could be: pairs and the second: relax
8 0
3 years ago
What is the pressure in a 5.00 L tank with<br> 7.10 moles of oxygen at 39.3 °C?
Katena32 [7]

Answer:

36.4 atm

Explanation:

To find the pressure, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = constant (0.0821 L*atm/mol*K)

-----> T = temperature (K)

Before you can plug the given values into the equation, you first need to convert Celsius to Kelvin.

P = ? atm                         R = 0.0821 L*atm/mol*K

V = 5.00 L                       T = 393 °C + 273.15 = 312.45 K

n = 7.10 moles

PV = nRT

P(5.00 L) = (7.10 moles)(0.0821 L*atm/mol*K)(312.45 K)

P(5.00 L) = 182.130

P = 36.4 atm

8 0
1 year ago
If an organic compound has a carbonyl group and a hydroxyl group, with the carbonyl group connected to two R groups, is it consi
34kurt

Answer:

A carboxyl group (COOH) is a functional group consisting of a carbonyl group (C=O) with a hydroxyl group (O-H) attached to the same carbon atom. Carboxyl groups have the formula -C(=O)OH, usually written as -COOH or CO2H.

6 0
2 years ago
If a solution has a [H+] of 9.3x10-11, what is the pH?
Rina8888 [55]

Answer:

<h2>10.03</h2>

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ {H}^{+} ]

From the question we have

ph =  -  log(9.3 \times  {10}^{ - 11} )  \\  = 10.0315...

We have the final answer as

<h3>10.03</h3>

Hope this helps you

4 0
3 years ago
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