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storchak [24]
3 years ago
5

Calculate the mass percent by volume of 42.6 g of glucose (C₆H₁₂O₆, MM = 180.2 g/mol) in 325 mL of solution.

Chemistry
1 answer:
expeople1 [14]3 years ago
4 0

Answer:

1.67 mol/L

Explanation:

(Mass of the component in the solution / Total mass of the solution) x 100

Other methods are:

Volume percentage:

Volume % of a component =

(Volume of the component/Total volume of the solution) x 100

Mass by volume percentage:

It is the mass of solute dissolved in 100 mL of the solution.

i.e. Mass by Volume percentage =

(Mass of solute in grams/Volume of solution in mL) x 100

Here's a point to be kept in mind :

Whenever we say mass or volume of the solution, you need to add the respective masses and volumes of ALL the components of the solution. Do NOT commit the error of taking the mass or volume of only the solute or solvent in the denominators of the above expressions.

The concentration of a solution is most of the time expressed as the number of moles of solute present in 1 Liter of the solution (also called molarity )

(There are also other ways to express concentration. Please follow this link. )

EXAMPLE:

(a) If 25 moles of NaCl are present in 100 L of a solution wherein H2O is the solvent, then the concentration of the solution is

25

100

=

0.25

mol⋅L

−

1

.

(b) What is the molarity of a solution prepared by dissolving 15.0 g of sodium hydroxide in enough water to make a total of 225 mL of solution?

Solution

Calculate the number of moles of solute present.

Moles of NaOH = 15.0 g NaOH ×

1

mol NaOH

40.00

g NaOH

= 0.375 mol NaOH

Calculate the number of litres of solution present.

Volume = 225 mL ×

1

L

1000

mL

= 0.225 L soln

Divide the number of moles of solute by the number of litres of solution.

Molarity =

0.375

mol

0.225

L

= 1.67 mol/L

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A 2.0% (w/v) solution of sodium hydrogen citrate, Na2C6H6O7, which also contains 2.5% (w/v) of dextrose, C6H12O6, is used as an
tamaranim1 [39]

Answer:

0.0847M is molarity of sodium hydrogen citrate in the solution

Explanation:

The 2.0%(w/v) solution of sodium hydrogen citrate contains 2g of the solute in 100mL of solution. To find the molarity of the solution we need to convert the mass of solute to moles using molar mass and the mL of solution to Liters because molarity is the ratio between moles of sodium hydrogen citrate and liters of solution.

<em>Moles Na2C6H6O7:</em>

<em>Molar Mass:</em>

2Na: 2*22.99g/mol: 45.98g/mol

6C: 6*12.01g/mol: 72.01g/mol

6H: 6*1.008g/mol: 6.048g/mol

7O: 7*16g/mol: 112g/mol

45.98g/mol + 72.01g/mol + 6.048g/mol + 112g/mol = 236.038g/mol

Moles of 2g:

2g * (1mol / 236.038g) = <em>8.473x10⁻³ moles</em>

<em />

<em>Liters solution:</em>

100mL * (1L / 1000mL) = <em>0.100L</em>

<em>Molarity:</em>

8.473x10⁻³ moles / 0.100L =

<h3>0.0847M is molarity of sodium hydrogen citrate in the solution</h3>
3 0
2 years ago
Read 2 more answers
How many atoms are there in each of the following substances?
juin [17]

To know the number of atoms, it will be necessary to use the formula of avogadro. We calculate the number of moles then we can calculate the number of avogadro.

The molar mass of:

Phosphorus = 31g / mol

Mercury = 200 g / mol

Bismuth = 209 g / mol

Strontium = 87 g / mol.

The number of avogadro (N) is 6.023 10 ^ 23

n = m (mass) / M  (molar mass)

number of atoms = n. N = m / M  . N

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Number of bismuth atoms = 1.8/209 . 6.023 10^23 = 5.18 10 ^ 21 atoms

Number of strontium atoms = 8.8 x 10-2 /87 . 6.023 10^23 = 6.09 10 ^ 20 atoms

3 0
3 years ago
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