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3 years ago

A circuit has a 10 Ω resistor connected to a 1.5 V dry cell. What is the current that can flow in the circuit?

1 answer:

8 0

Here is the highly detailed, arcane, complex, technical form of Ohm's Law that is needed in order to answer this question ===> I = V / R .

Current = (voltage) / (resistance)

Current = (1.5 V) / (10 Ω)

<em>Current = 0.15 Ampere</em>

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A police car waits in hiding slightly off the highway. A speeding car is spotted by the police car traveling at speed s = 27.6 m

andriy [413]

Answer:

$t=\frac{2s}{a}=25.56s$

Explanation:

The distance traveled by the speeding car will be $d_s=st$ , where $s=27.6m/s$ .

The distance traveled by the police car will be given by the formula:

$d=v_{0}t+\frac{at^2}{2}$ , where $a=2.16m/s^2$ and $v_0=0m/s$ since it departs from rest, thus having $d=\frac{at^2}{2}$ .

The police car will reach the speeding car when those distances are the same, or $s=d$ , so we will have:

$st=\frac{at^2}{2}$

Which means:

$t=\frac{2s}{a}$

This is the expression asked, but we can use our values:

$t=\frac{2s}{a}=\frac{2(27.6m/s)}{(2.16m/s^2)}=25.56s$

6 0

3 years ago

1. How much force would you have to apply to a 15kg object in order to accelerate it!<br> a 2 m/s?

mihalych1998 [28]

30N

Explanation:

Given parameters:

Mass of object = 15kg

Acceleration = 2m/s

Unknown:

Force = ?

Solution:

Force is given as the product of mass and acceleration:

F = m x a

m is the mass

a is the acceleration

Inputting the parameters:

F = 15 x 2 = 30N

The unit of force is newtons, N .

Learn more:

Force brainly.com/question/10470406

#learnwithBrainly

3 0

3 years ago

A wave has a period of 2 seconds and a wavelength of 4 meters.Calculate its frequency and speed.

Lana71 [14]

F=l/t
f=4/2
f=2m/s

Hope this helps

3 0

3 years ago

Read 2 more answers

How can an individual benefit from participating in the recommended amount of physical activity?

Orlov [11]

It will help them stay in better shape resulting in better health, being more physically active, and staying happier as a result.

3 0

3 years ago

You have a radioactive sample with a half-life of 1 hour. At t = 1 hour, a Geiger counter measures its radiation at 40 counts/mi

Mama L [17]

Answer:

Explanation:

Given that, .

The half-life of a radioactive element is

t½ = 1 hr.

At the first hour, the radioactive element has 40 counts/minute

After 4 hours it has 5 counts/minute

So,

We want to filled the table.

0 hours, I.e at the start

40 counts/mins × 2 = 80 counts / mis

First half-life (first hour) is

40 counts/mins

Second half-life (second hour)

40 counts/mins × ½ = 20 counts/mins

Third half-life (third hour)

40 counts/mins × ¼ = 10 counts / mins

Fourth half life (fourth hour)

40 counts/mins × ⅛ = 5 counts / mins

So, the table is

Time........................Geiger Counter Rate

0 hours.................... 80 counts / minutes

1 hour........................ 40 counts / minutes

2 hours..................... 20 counts / minutes

3 hours..................... 10counts / minutes

4 hours...................... 5 counts / minute

6 0

3 years ago