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Temka [501]
3 years ago
10

A wave has a period of 2 seconds and a wavelength of 4 meters.Calculate its frequency and speed.

Physics
2 answers:
Sloan [31]3 years ago
5 0

Answer:

f = 0.5 Hz

v = 8 m/s

Explanation:

f = 1/T

f = 1/(2) = 0.5 Hz

v = λf

v = (2)(4) = 8 m/s

Lana71 [14]3 years ago
3 0
F=l/t
f=4/2
f=2m/s

Hope this helps

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What is the name of the chart that contain elements?​
prisoha [69]

Answer:

Element Chart

Explanation:

It is a chart that provides many different elements.

7 0
3 years ago
A colloidal liquid in a has is called
S_A_V [24]
Aerosol is the answer
8 0
3 years ago
1. A perspex box has a 10 cm square base and contains water to a height of 10 cm. A piece of rock of mass 600g is lowered into t
AnnZ [28]

Answer:

(a) The volume of water is 100 cm³

(b) The volume of the rock is 20 cm³

(c) The density of the rock is 30 g/cm³

Explanation:

The given parameters of the perspex box are;

The area of the base of the box, A = 10 cm²

The initial level of water in the box, h₁ = 10 cm

The mass of the rock placed in the box, m = 600 g

The final level of water in the box, h₂ = 12 cm

(a) The volume of water in the box, 'V', is given as follows;

V = A × h₁

∴ The volume of water in the box, V = 10 cm² × 10 cm = 100 cm³

The volume of water in the box, V = 100 cm³

(b) When the rock is placed in the box the total volume, V_T, is given by the sum of the rock, V_r, and the  water, V, is given as follows;

V_T = V_r + V

V_T = A × h₂

∴ V_T = 10 cm² × 12 cm = 120 cm³

The total volume, V_T = 120 cm³

The volume of the rock, V_r = V_T - V

∴ V_r = 120 cm³ - 100 cm³ = 20 cm³

The volume of the rock, V_r = 20 cm³

(c) The density of the rock, ρ = (Mass of the rock, m)/(The volume of the rock)

∴ The density of the rock, ρ = 600 g/(20 cm³) = 30 g/cm³

8 0
3 years ago
A 5.00 kg mass is placed on top of a vertical spring, which compresses a distance of 3.13 cm. Calculate the force constant (in N
77julia77 [94]

Answer:

<h2>1567.09 N/m</h2>

Explanation:

Step one:

given data

mass m=5kg

compression x= 3.13cm to m= 0.0313m

<em>According to Hooke's law, provided the elastic limit of an elastic material is not exceeded the extension e is directly proportional to the applied force</em>

F=ke

where

k= spring constant in N/m

e= extension/compression in

Step two:

assume g= 9.81m/s^2

F=mg

F=5*9.81

F=49.05N

substitute in the expression F=ke

49.05=k*0.0313

k=49.05/0.0313

k=1567.09 N/m

<u>The force constant (in N/m) of the spring is 1567.09 N/m</u>

8 0
3 years ago
If you increase the force acting on an object, what will happen to the object's motion
Mama L [17]
Force is directly proportional to rate of change of velocity so it increasing, velocity (motion of the object) will also increase.

Hope this helps!
6 0
3 years ago
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