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adoni [48]
3 years ago
14

A piggy bank contains a nickels, dimes and quarters. There are five more dimes than nickels and twice as many quarters as dimes.

The total value for the coins is $7.55. How many of each type of coins is in the piggy bank? # of nickels:__________ # of dimes:__________ # of quarters:___________
Mathematics
1 answer:
Natasha2012 [34]3 years ago
4 0

Answer:

34 nickels, 39 dimes, 78 quarters

Step-by-step explanation:

q = quarters, d = dimes, n = nickels

n = d - 5

q = 2d

.25q + .10d + .05n = 7.55

<em>Plug in the first 2 equations into the third one</em>

.5d + .10d + .05(d - 5) = 7.55

<em>Open up the Parenthesis</em>

.5d + .10d + .5d - .25 = 7.55

<em>Combine Like Terms</em>

.2d - .25 = 7.55-->

.2d = 7.8 -->

d = 39 -->

n = 39 - 5 = 34

q = 2(39) = 78

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Step-by-step explanation:

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2 years ago
An electronic product contains 48 integrated circuits. The probability that any integrated circuit is defective is 0.01, and the
BigorU [14]

Answer:

0.6173 = 61.73% probability that the product operates.

Step-by-step explanation:

For each integrated circuit, there are only two possible outcomes. Either they are defective, or they are not. The integrated circuits are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

An electronic product contains 48 integrated circuits.

This means that n = 48

The probability that any integrated circuit is defective is 0.01.

This means that p = 0.01

The product operates only if there are no defective integrated circuits. What is the probability that the product operates?

This is P(X = 0). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{48,0}.(0.01)^{0}.(0.99)^{48} = 0.6173

0.6173 = 61.73% probability that the product operates.

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3 years ago
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1 hour and 15 minutes
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7 0
3 years ago
Answer quickly for 50 points, thank you.
Kaylis [27]

The incorrect answer is B.

All you have to do is plug in x to the formulas and see if the are equal.

4x - 2 = 3x + 6

4(8) - 2 = 3(8) + 6

30 = 30

CORRECT


The second is not only not equal, but it is the wrong kind of formula for what you are trying to prove there.

Hope that helps!

6 0
3 years ago
Read 2 more answers
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