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pshichka [43]
3 years ago
15

5. Balance the equation and state the limiting reagent in the following reaction:

Chemistry
1 answer:
mr Goodwill [35]3 years ago
8 0

Answer:

5. 2 Al  3 Cl2 and 2 AlCl3

Cl2 is limiting

(It has the highest coefficients, but that's not always true. If they give you the number of grams for each make sure to work the math out)

6. C

(As the pressure increases there is less volume for the molecules to move around, therefore the molecules will be closer together, allowing for more collisions.)

7.  b

(if the temperature is increases so will the rate of the reaction. The increase in temperature will allow for the molecules to move at a faster rate, allowing for more collisions (reactions) between them.

8. d

(dynamic equilibrium is the state at which the reaction is consistently moving, there fore the amounts should remain the same)

9. A

(a catalyst will lower the the pathway of activation energy because it's meant to speed up a reaction)

bro youre on your own after this, im tired

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Identify an alkene and carboxylic acid using primary observations
ehidna [41]

Answer:

The general formula for the carboxylic acids is C nH 2n+1COOH (where n is the number of carbon atoms in the molecule, minus 1).

Explanation:

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4 0
3 years ago
Hòa tan hoàn toàn 1,93 gam hỗn hợp 2 kim loại Fe và Al vào dd HCl dư, sau phản ứng thu được m gam muối và 1,456 lít khí H2 ở đkt
Lostsunrise [7]

Answer:

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Explanation:

8 0
3 years ago
1. In what ways does an organism’s mode of reproduction impact the diversity of its offspring? (Asexual vs. Sexual)
Katen [24]

Answer:

<u>Asexual reproduction</u> = An exact copy of the reproducer

<u>Sexual reproduction</u> = Genetic variation into the organism if a random mutation in the organism's DNA is transmitted to offspring.

Explanation:

Example of Asexual Reproduction diversity - A red apple has apple seeds. You plant the red apple seeds, and it grows up to be no different than the apple before it.

Sexual reproduction Example of diversity -Two parents are of different ethnicities. The female gets pregnant, but because of the different genetics from both of the parents, the child will inherit their genetics + some random mutation in the DNA.  

This impacts the diversity of the offspring because it can be an exact copy of the reproducer (Asexual), or significantly different with some similarities if the mode of reproduction was sexual.

I really hope this helps you! Please tell me if it did or not. Good luck with your assignment/exam/quiz!

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7 0
2 years ago
Read 2 more answers
What mass of cu(s)cu(s) is electroplated by running 14. 5 aa of current through a cu2 (aq)cu2 (aq) solution for 4. 00 hh?
galina1969 [7]

The mass of Copper electroplated is 68.76 g

<h3>What is electroplating?</h3>

The process of plating a metal onto another is known as electroplating.

It is often used to prevent corrosion of metal or for the decorative purposes

In this process, electric current is passed through an aqueous solution containing dissolved cations.

The dissolved cations are reduced developing a thin metal coating on the electrode.

At cathode,

Cu^{2+}(aq) + 2e^-\rightarrow      Cu(s)

Current, I = 14.5 A

Time, t = 4 hrs = 4×60×60 = 14400 sec

Charge, q = It = 14.5×14400= 208800 C

Copper metal deposited by 2×96487 C = 63.55 g

Copper metal deposited by 208800 C = \frac{63.55 \times208800}{2\times96487}

                                                         = 68.76g

Hence, The mass of Copper electroplated is 68.76 g

Learn more about electroplating:

brainly.com/question/22104403

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4 0
1 year ago
Read 2 more answers
Calculate E ° for the half‑reaction, AgCl ( s ) + e − − ⇀ ↽ − Ag ( s ) + Cl − ( aq ) given that the solubility product constant
antoniya [11.8K]

Answer: The value of E^{o} for the half-cell reaction is 0.222 V.

Explanation:

Equation for solubility equilibrium is as follows.

          AgCl(s) \rightleftharpoons Ag^{+}(aq) + Cl^{-}(aq)

Its solubility product will be as follows.

       K_{sp} = [Ag^{+}][Cl^{-}]

Cell reaction for this equation is as follows.

     Ag(s)| AgCl(s)|Cl^{-}(0.1 M)|| Ag^{+}(1.0 M)| Ag(s)

Reduction half-reaction: Ag^{+} + 1e^{-} \rightarrow Ag(s),  E^{o}_{Ag^{+}/Ag} = 0.799 V

Oxidation half-reaction: Ag(s) + Cl^{-}(aq) \rightarrow AgCl(s) + 1e^{-},   E^{o}_{AgCl/Ag} = ?

Cell reaction: Ag^{+}(aq) + Cl^{-}(aq) \rightarrow AgCl(s)

So, for this cell reaction the number of moles of electrons transferred are n = 1.

    Solubility product, K_{sp} = [Ag^{+}][Cl^{-}]

                                               = 1.77 \times 10^{-10}

Therefore, according to the Nernst equation

           E_{cell} = E^{o}_{cell} - \frac{0.0592 V}{n} log \frac{[AgCl]}{[Ag^{+}][Cl^{-}]}

At equilibrium, E_{cell} = 0.00 V

Putting the given values into the above formula as follows.

         E_{cell} = E^{o}_{cell} - \frac{0.0592 V}{n} log \frac{[AgCl]}{[Ag^{+}][Cl^{-}]}

        0.00 = E^{o}_{cell} - \frac{0.0592 V}{1} log \frac{1}{[Ag^{+}][Cl^{-}]}    

       E^{o}_{cell} = \frac{0.0592}{1} log \frac{1}{K_{sp}}

                  = 0.0591 V \times log \frac{1}{1.77 \times 10^{-10}}

                  = 0.577 V

Hence, we will calculate the standard cell potential as follows.

           E^{o}_{cell} = E^{o}_{cathode} - E^{o}_{anode}

       0.577 V = E^{o}_{Ag^{+}/Ag} - E^{o}_{AgCl/Ag}

       0.577 V = 0.799 V - E^{o}_{AgCl/Ag}

       E^{o}_{AgCl/Ag} = 0.222 V

Thus, we can conclude that value of E^{o} for the half-cell reaction is 0.222 V.

3 0
3 years ago
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