All categories

3 years ago

Any one know the answer?

Engineering

1 answer:

ella [17]3 years ago

8 0

Answer:

151.2 N

Explanation:

The upward force at A is 135/(135+325) times the total weight of the generator. The CW torque about point O that produces is ...

(460 mm)(135/460)(160 kg)(9.8 m/s^2) = 211.68 N·m

For F to produce half that torque, it must be ...

F(0.7 m) = (211.68 N·m)/2

F = 211.68 N·m/(1.4 m) = 151.2 N

You might be interested in

In the following code, determine the values of the symbols here and there. Write the object code in hexadecimal. (Do not predict

allsm [11]

Answer:

Answer explained below

Explanation:

The value of here is 9

The value of there is hexadecimal value of DECO here, d = 0x39 aaaa (aaaa is the memory address of here )

We have the object code :-

let's take there address is 0x0007

0x0005 BR there :- 0x120020

0x0007 here: .WORD 9

310003 there: DECO here,d - 0x390007

310005 STOP

.END

4 0

3 years ago

The annual storage in Broad River watershed is 0 cm/y. Annual precipitation is 100 cm/y and evapotranspiration is 50 cm/y. The s

REY [17]

Answer:

0.34232

Explanation:

See attachment

3 0

3 years ago

Read 2 more answers

Thoughts about drinking and driving

poizon [28]

Answer: it’s very bad behavior and can be dangerous

Explanation:

8 0

3 years ago

Read 2 more answers

What are the main microsoft ware packages widely used today

RSB [31]

Answer:

» Microsoft word ( word processing )

» Microsoft powerpoint ( presentation )

» Microsoft access ( database mamagement )

» Microsoft excel ( spread sheets )

Explanation:

$.$

7 0

3 years ago

Read 2 more answers

A consolidation test was performed on a sample of fine-grained soil sample taken from a depth such that the vertical effective s

Scorpion4ik [409]

Answer:

The settlement that is expected is 1.043 meters.

Explanation:

Since the pre-consolidation stress of the layer is equal to the effective stress hence we conclude that the soil is normally consolidated soil

The settlement due to increase in the effective stress of a normally consolidated soil mass is given by the formula

$\Delta H=\frac{H_oC_c}{1+e_o}log(\frac{\bar{\sigma_o}+\Delta \bar{\sigma }}{\bar{\sigma_o}})$

where

'H' is the initial depth of the layer

$C_c$ is the Compression index

$e_o$ is the inital void ratio

$\bar{\sigma_o}$ is the initial effective stress at the depth

$\Delta \bar{\sigma_o}$ is the change in the effective stress at the given depth

Applying the given values we get

$\Delta H=\frac{8\times 0.3}{1+0.87}log(\frac{154+28}{154})=1.04$

3 0

3 years ago

Any one know the answer?​

Any one know the answer?