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maksim [4K]
3 years ago
7

Any one know the answer?​

Engineering
1 answer:
ella [17]3 years ago
8 0

Answer:

  151.2 N

Explanation:

The upward force at A is 135/(135+325) times the total weight of the generator. The CW torque about point O that produces is ...

  (460 mm)(135/460)(160 kg)(9.8 m/s^2) = 211.68 N·m

For F to produce half that torque, it must be ...

  F(0.7 m) = (211.68 N·m)/2

  F = 211.68 N·m/(1.4 m) = 151.2 N

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Now replacing the critical stress with 54.8

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\sigma_c=\frac{54.8}{1\sqrt{\pi  \times 0.2\times10^{-3}} } \\\\=\frac{54.8}{\sqrt{6.283\times10^{-4}} } \\\\=\frac{54.8}{0.025} \\\\=2186.20Mpa

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