A movie features dangerous stunts including jumping from a helicopter, riding on the hood of a speeding car, and a number of oth
er acrobatic stunts. The director has hired a stunt double to perform these stunts. In the filming of the helicopter scene, the stunt double is released from a height of 10,000m. Assume the only forces acting on the stunt double are gravity and air resistance. The force of air resistance is assumed to be proportional to the velocity with proportionality constant λ = 10. Assume the stunt double has a mass of 60kg and the force of gravity is −9.81m/s^2.
Required:
Construct a differential equation which models the velocity of the falling stunt double. Explain the reasoning behind how you constructed the model you chose to use. Discuss any potential shortcomings of your model. Describe any initial conditions associated with your model.
Required:
Construct a differential equation which models the velocity of the falling stunt double. Explain the reasoning behind how you constructed the model you chose to use. Discuss any potential shortcomings of your model. Describe any initial conditions associated with your model.
1 answer:
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Answer:
Diego is correct.
He has correctly divided 1 in groups of .
Step-by-step explanation:
The question 'How many groups of 5/6 are in 1?' means that we need to divided 1 into groups of .
When we form groups from a given total, we divided the total by the size of the group.
If we are dividing number of people in groups of
number of people, then the expression to find the number of groups formed can be given as:
⇒
For this question the data given is:
So, the number of groups formed can be given as:
⇒
When divisor is a fraction, then we multiply the reciprocal of the divisor with the dividend.
⇒
⇒
In order to convert fraction to mixed number we will divide numerator with denominator and then write the quotient as whole number, remainder as numerator and the denominator remains as it is.
On dividing 6 by 5, the quotient =1 and remainder =1. Thus the mized number is:
⇒
Thus, there are or
groups in 1. This matches with Diego's answer and hence he is correct.