Answer:
An equation of the line that passes through the point(2,−5) and is parallel to the line 6x+y=6 is:
Step-by-step explanation:
The slope-intercept form of the line equation
![y = mx+b](https://tex.z-dn.net/?f=y%20%3D%20mx%2Bb)
where m is the slope and b is the y-intercept
Given the equation
![6x+y=6](https://tex.z-dn.net/?f=6x%2By%3D6)
Writing in the slope-intercept form of the line equation
![y = -6x + 6](https://tex.z-dn.net/?f=y%20%3D%20-6x%20%2B%206)
comparing with the slope-intercept form of the line equation
y = mx+b
Thus, the slope of line = m = -6
We know that the parallel lines have the same slopes.
Thus, the slope of the parallel line is also -6.
As the line passes through the point (2,−5).
Thus, using the point-slope form of the line equation
![y-y_1=m\left(x-x_1\right)](https://tex.z-dn.net/?f=y-y_1%3Dm%5Cleft%28x-x_1%5Cright%29)
where m is the slope and (x₁, x₂) is the point
substituting the values m = -6 and the point (2,−5)
![y-y_1=m\left(x-x_1\right)](https://tex.z-dn.net/?f=y-y_1%3Dm%5Cleft%28x-x_1%5Cright%29)
![y - (-5) = -6 (x - 2)](https://tex.z-dn.net/?f=y%20-%20%28-5%29%20%3D%20-6%20%28x%20-%202%29)
![y+5=-6\left(x-2\right)](https://tex.z-dn.net/?f=y%2B5%3D-6%5Cleft%28x-2%5Cright%29)
subtract 5 from both sides
![y+5-5=-6\left(x-2\right)-5](https://tex.z-dn.net/?f=y%2B5-5%3D-6%5Cleft%28x-2%5Cright%29-5)
![y=-6x+7](https://tex.z-dn.net/?f=y%3D-6x%2B7)
Therefore, an equation of the line that passes through the point(2,−5) and is parallel to the line 6x+y=6 is: