Physiological pH is between 7.37 and 7.43
Lysine is a basic amino acid, which means
it has two NH2 groups and one COOH group.
Lysine pKas are: 2.16, 9.06 and 10.05
At low pH (lower than the first pKa, in
this case: lower than 2.16) the three groups are protoned. As you increase pH,
the first group to lose its proton is the acid group, then the alpha-amino
group and then the R-amino group. You will have everything non protoned at a
high pH (higher than the highest pKa, in this case: 10.05).
Physiological pH is higher than the lowest
pKa and lower than the middle pKa, so it’s the second case: the acid is
not protoned, the R-amino is protoned and the alpha amino is protoned.
Protoned aminos are cations: NH3+.
That would be phosphorus. It’s electron configuration is 1s^2 2s^2 2p^6 3s^2 3p^3
Answer : The correct option is, (C) 6
Explanation :
Oxidation-reduction reaction : It is a reaction in which oxidation and reduction reaction occur simultaneously.
Oxidation reaction : It is the reaction in which a substance looses its electrons. In this oxidation state increases.
Reduction reaction : It is the reaction in which a substance gains electrons. In this oxidation state decreases.
The given unbalanced chemical reaction is,
Half reactions of oxidation and reduction are :
Oxidation : ......(1)
Reduction : .......(2)
In order to balance the electrons, we multiply equation 1 by 2 and equation 2 by 3, we get:
Oxidation : ......(1)
Reduction : .......(2)
The overall balanced chemical reaction will be:
From this reaction we conclude that the electrons are getting transferred from iron to iodine and the number of electrons transferred are 6 electrons.
Hence, the correct option is, (C) 6
D) The enzyme and substrate form an enzyme-substrate complex
An enzyme is a protein molecule that acts as a catalyst in biological reactions. It does so by acting on a substrate which is specific to its shape. The substrate binds to the enzyme's active site, forming the enzyme-substrate complex. The reaction is then complete and the product detaches from the enzyme molecule. The enzyme is then free to act on other substrate molecules.