Answer:
The precipitated are option a and d.
Explanation:
2 LiI(aq) +Hg2(NO3)2(aq) → Hg2I2(s) ↓ + 2 LiNO3(aq)
Cation Hg2+ 2 in the presence of iodide, a precipitated is formed.
Zn(s) + 2AgNO3(aq) → 2 Ag(s) ↓ +Zn(NO3)2(aq)
Zinc starts to get rid, and some white particles also stick to it. Afterwards the solution becomes cloudy and a precipitate appears, which is the solid silver
Answer:
Blank 1 - 2
Blank 2 - 4
Blank 3 - 3
Explanation:
The unbalanced chemical equation given in the question is as follows:
Au2O3 → Au + O2
To balance a chemical equation, the number of atoms of each element on both sides of the equation (reactants and product) must be the same. Based on this explanation, the balanced chemical equation is as follows:
2Au2O3 → 4Au + 3O2
- 4 atoms of gold (Au) on both sides
- 6 atoms of oxygen on both sides
Hence, based on the question, blank 1, 2 and 3 are 2, 4 and 3 respectively.
The enthalpy of combustion of 1 mole of acetylene for the reaction using the information in the table (attached as figure) is - 1,256 kJ/mol
<h3>What is Enthalpy of combustion ?</h3>
The enthalpy of combustion of a substance is defined as the heat energy given out when one mole of a substance burns completely in oxygen.
Hence, The enthalpy of combustion of 1 mole of acetylene for the reaction using the information in the table is - 1,256 kJ/mol
Learn more about Enthalpy here ;
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Answer:
Acceleration is the correct answer. Hope this helps!
Explanation:
