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Nastasia [14]
3 years ago
6

Explain why the statement “The speed of light is 300 million m/s” is not always correct.

Chemistry
1 answer:
levacccp [35]3 years ago
5 0

Because the speed of light is determined by the medium that is it in. If light is in a vacuum it goes 300 million meters per second but it is slower in air, and even slower in water because water is more dense than the previous two.

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What type of nuclear decay is shown by the reaction below?
pantera1 [17]

Answer:

B. Alpha

Explanation:

Alpha decays always split into an element and He.

Beta decays always split into an element and e- (eletrons).

Gamma decays always split into an element and radiation.

3 0
3 years ago
The half life for the decay of carbon-14 is 5.73 x 10 years. Suppose the activity due to the radioactive decay of the carbon-14
Elena-2011 [213]

Answer:

Age of the atifact is 4.2\times 10^{2} years

Explanation:

  • For first -order radioactive decay- A_{t}=A_{0}(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}
  • A_{t} represents activity of radioactive nuclide after t time, A_{0} represents initial activity of radioactive nuclide and t_{\frac{1}{2}} represents half-life
  • Here, A_{t}=19Bq, A_{0}=20Bq and t_{\frac{1}{2}}=5.73\times 10^{3}years

Plug-in all the given values in the above equation-

19=20\times (\frac{1}{2})^{\frac{t}{5.73\times 10^{3}}}

or, t=4.2\times 10^{2}

So, age of the atifact is 4.2\times 10^{2} years

6 0
3 years ago
calculate the volume that will be occupied by 350 ml of oxygen measured at 720 mm hg, when the pressure changed to 630 mm hg
likoan [24]

Answer:

406.45mL

Explanation:

The following data were obtained from the question:

V1 = 350mL

P1 = 720mmHg

P2 = 630mmHg

V2 =?

The new volume can be obtain as follows:

P1V1 = P2V2

720 x 350 = 620 x v2

Divide both side by 620

V2 = (720 x 350) /620

V2 = 406.45mL

The new volume of the gas is 406.45mL

8 0
3 years ago
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3 years ago
Calculate the de Broglie wavelength of a body of mass 1 kg moving with a velocity of
skelet666 [1.2K]

Answer:

4.42 × 10⁻³⁷ m

Explanation:

Step 1: Given and required data

  • Mass of the body (m): 1 kg
  • Velocity of the body (v): 1500 m/s
  • Planck's constant (h): 6.63 × 10⁻³⁴ J.s

Step 2: Calculate the de Broglie wavelenght (λ) of the body

We will use de Broglie's equation.

λ = h / m × v

λ = (6.63 × 10⁻³⁴ J.s) / 1 kg × (1500 m/s) = 4.42 × 10⁻³⁷ m

6 0
2 years ago
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