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3 years ago

What effect do increasing amounts of greenhouse gases have on earth and the organisms that live here?

Physics

2 answers:

pickupchik [31]3 years ago

5 0

Answer and Explanation:

The increasing amounts of greenhouse gases causes climate change and global warming, sea level rises and oceans become warmer.

When prolonged into the future and no actions are being taken; drastic droughts will happen which threatens agricultural in an extreme manner, wildlife living in the forests will be pressurized, and animals/organisms living in the ocean will be affected too due to rising temperature causing the reduced Oxygen effects.

The examples include: the melting of Arctic ice endangering the polar bears, fishes and aquatic marines will die at part of the oceans which has higher temperature (lack of oxygen), poorer regions will have adverse impacts on the human being due to agriculture deterioration and lack of proper system and social readiness to adapt to climate change.

To fight climate change, we must reduce carbon pollution (burning of coals which releases large carbon dioxide/monoxide etc.) through setting up of policies by multinational companies, greener business to reduce emissions, and help people to adapt to climate change or at least educate people about climate change.

Eduardwww [97]3 years ago

3 0

Answer:

An increase in the greenhouse gases implies an increase in the average temperature of the atmosphere which might lead to extreme weather conditions, rise of sea levels etc It will affects animal food sources and habitats.

Explanation:

Greenhouse gases covers the earth like a shield or covering. Human activities for example industrialization, deforestation, burning of coal, natural gases and fossil fuels etc adds extra layers of thickness to the already existing greenhouse gases thereby making it impenetrable by heat. This trapped heat is what is responsible for the increased average global temperature.

The effects are numerous and can be detrimental to say the least. When there is an increase in temperature, algae(water plant) which acts as a direct source of food for small fishes dies off which could lead to extinction of smaller fish species which is a direct food source for bigger fishes and the cycle continues which translates into reduced food supply for animals(including man).

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A hawk is flying horizontally at 18.0 m/s in a straight line, 230 m above the ground. A mouse it has been carrying struggles fre

Lisa [10]

Answer:

a) vd = 47.88 m/s

b) θ = 80.9°

c) t = 6.8 s

Explanation:

In the situation of the problem, you can assume that the trajectory of the hawk and the trajectory of the mouse form a rectangle triangle.

One side of the triangle is the horizontal trajectory of the hawk after 2.00s of flight, the other side of the triangle is the distance traveled by the mouse when it is falling down. And the hypotenuse is the trajectory of the hawk when it is trying to recover the mouse.

(a) In order to calculate the diving speed of the hawk, you first calculate the hypotenuse of the triangle.

One side of the triangle is c1 = (18.0m/s)(2.0s) = 36m

The other side of the triangle is c2 = 230m - 3m = 227 m

Then, the hypotenuse is:

$h=\sqrt{(36m)^2+(227m)^2}=229.83m$ (1)

Next, it is necessary to calculate the falling down time of the mouse, this can be done by using the following formula:

$y=y_o+v_ot+\frac{1}{2}gt^2$ (2)

yo: initial height = 230m

vo: initial vertical speed of the mouse = 0m/s

g: gravitational acceleration = -9.8m/s^2

y: final height of the mouse = 3 m

You replace the values of the parameters in (2) and solve for t:

$3=230-4.9t^2\\\\t=\sqrt{\frac{227}{4.9}}=6.8s$

The hawk traveled during 2.00 second in the horizontal trajectory, hence, the hawk needed 6.8s - 2.0s = 4.8 s to travel the distance equivalent to the hypotenuse to catch the mouse.

You use the value of h and 4.8s to find the diving speed of the hawk:

$v_d=\frac{229.83m}{4.8s}=47.88\frac{m}{s}$

The diving speed of the Hawk is 47.88m/s

(b) The angle is given by:

$\theta=cos^{-1}(\frac{c_1}{h})=cos^{-1}(\frac{36m}{229.83m})=80.9 \°$

Then angle between the horizontal and the trajectory of the Hawk when it is descending is 80.9°

(c) The mouse is falling down during 6.8 s

4 0

3 years ago

A semicircular plate with radius 6 m is submerged vertically in water so that the top is 2 m above the surface. Express the hydr

dalvyx [7]

Answer: 313920

Explanation:First, we’re going to assume that the top of the circular plate surface is 2 meters under the water. Next, we will set up the axis system so that the origin of the axis system is at the center of the plate.

Finally, we will again split up the plate into n horizontal strips each of width Δy and we’ll choose a point y∗ from each strip. Attached to this is a sketch of the set up.

The water’s surface is shown at the top of the sketch. Below the water’s surface is the circular plate and a standard xy-axis system is superimposed on the circle with the center of the circle at the origin of the axis system. It is shown that the distance from the water’s surface and the top of the plate is 6 meters and the distance from the water’s surface to the x-axis (and hence the center of the plate) is 8 meters.

The depth below the water surface of each strip is,

di = 8 − yi

and that in turn gives us the pressure on the strip,

Pi =ρgdi = 9810 (8−yi)

The area of each strip is,

Ai = 2√4− (yi) 2Δy

The hydrostatic force on each strip is,

Fi = Pi Ai=9810 (8−yi) (2) √4−(yi)² Δy

The total force on the plate is found on the attached image.

5 0

3 years ago

Is this the actual answer??

Nastasia [14]

It probably is the actual answer.

3 0

3 years ago

20 Accelerated motion is represented by a<br> line on a nonlinear distance time graph.

Varvara68 [4.7K]

Curved line

Explanation:

Acceleration of motion is represented by a curved line on a non-linear distance-time graph.

The acceleration of a non-linear motion is depicted using a parabola which is a curve. This implies that the velocity is constantly changing and the distance covered by the body is also changing with equal amount of time.