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3 years ago

What effect do increasing amounts of greenhouse gases have on earth and the organisms that live here?

Physics

2 answers:

pickupchik [31]3 years ago

5 0

Answer and Explanation:

The increasing amounts of greenhouse gases causes climate change and global warming, sea level rises and oceans become warmer.

When prolonged into the future and no actions are being taken; drastic droughts will happen which threatens agricultural in an extreme manner, wildlife living in the forests will be pressurized, and animals/organisms living in the ocean will be affected too due to rising temperature causing the reduced Oxygen effects.

The examples include: the melting of Arctic ice endangering the polar bears, fishes and aquatic marines will die at part of the oceans which has higher temperature (lack of oxygen), poorer regions will have adverse impacts on the human being due to agriculture deterioration and lack of proper system and social readiness to adapt to climate change.

To fight climate change, we must reduce carbon pollution (burning of coals which releases large carbon dioxide/monoxide etc.) through setting up of policies by multinational companies, greener business to reduce emissions, and help people to adapt to climate change or at least educate people about climate change.

Eduardwww [97]3 years ago

3 0

Answer:

An increase in the greenhouse gases implies an increase in the average temperature of the atmosphere which might lead to extreme weather conditions, rise of sea levels etc It will affects animal food sources and habitats.

Explanation:

Greenhouse gases covers the earth like a shield or covering. Human activities for example industrialization, deforestation, burning of coal, natural gases and fossil fuels etc adds extra layers of thickness to the already existing greenhouse gases thereby making it impenetrable by heat. This trapped heat is what is responsible for the increased average global temperature.

The effects are numerous and can be detrimental to say the least. When there is an increase in temperature, algae(water plant) which acts as a direct source of food for small fishes dies off which could lead to extinction of smaller fish species which is a direct food source for bigger fishes and the cycle continues which translates into reduced food supply for animals(including man).

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Time dilation: A missile moves with speed 6.5-10 m/s with respect to an observer on the ground. How long will it take the missil

tatyana61 [14]

Answer:

The time taken by missile's clock is $4.6\times 10^{6} s$

Solution:

As per the question:

Speed of the missile, $v_{m = 6.5\times 10^{3}} m/s$

Now,

If 'T' be the time of the frame at rest then the dilated time as per the question is given as:

T' = T + 1

Now, using the time dilation eqn:

$T' = \frac{T}{\sqrt{1 + (\frac{v_{m}}{c})^{2}}}$

$\frac{T'}{T} = \frac{1}{\sqrt{1 + (\frac{v_{m}}{c})^{2}}}$

$\frac{T + 1}{T} = \frac{1}{\sqrt{1 + (\frac{v_{m}}{c})^{2}}}$

$1 + \frac{1}{T} = \frac{1}{\sqrt{1 + (\frac{v_{m}}{c})^{2}}}$

$1 + \frac{1}{T} = (1 + (\frac{v_{m}}{c})^{2})^{- \frac{1}{2}}$ (1)

Using binomial theorem in the above eqn:

We know that:

$(1 + x)^{a} = 1 + ax$

Thus eqn (1) becomes:

$1 + \frac{1}{T} = 1 - \frac{- 1}{2}.\frac{v_{m}^{2}}{c^{2}}$

$T = \frac{2c^{2}}{v_{m}^{2}}$

Now, putting appropriate values in the above eqn:

$T = \frac{2(3\times 10^{8})^{2}}{(6.5\times 10^{3})^{2}}$

$T = 4.6\times 10^{6} s$

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3 years ago

Which best describes a major characteristic of both volcanoes and earthquakes? they are centered at the poles?

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Answer:

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2 years ago

The intensity I of light varies inversely as the square of the distance D from the source. If the intensity of illumination on a

emmasim [6.3K]

The intensity on a screen 20 ft from the light will be 0.125-foot candles.

<h3>What is the distance?</h3>

Distance is a numerical representation of the length between two objects or locations.

The intensity I of light varies inversely as the square of the distance D from the source;

I∝(1/D²)

The ratio of the intensity of the two cases;

$\rm \frac{I_1}{I_2} =(\frac{D_2}{D_1} )^2\\\\ \rm \frac{2}{I_2} =(\frac{20}{5} )^2\\\\ \frac{2}{I_2} =4^2 \\\\ I_2= \frac{2}{16} \\\\ I_2= 0.125 \ foot-candles$

Hence, the intensity on a screen 20 ft from the light will be 0.125 foot-candles

To learn more about the distance refer to the link;

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2 years ago

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3 years ago

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