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kaheart [24]
2 years ago
6

RP COME AND GET IT!!!!!!!!

Physics
2 answers:
tamaranim1 [39]2 years ago
8 0

Answer:

wait what

Explanation:

can i have brainliest plz

Ahat [919]2 years ago
6 0
I need someone to help me with my finals!!!!
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Nuclear fusion occurs in stars.<br> a. True<br> b. False
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Firlakuza [10]

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What is the name
Molodets [167]

Answer:

<h3>It's called Resistance! </h3>

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2 years ago
W=90 kg×4n/kg<br>Please halp me i need it ​
kiruha [24]

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5 0
3 years ago
A small box is held in place against a rough vertical wall by someone pushing on it with a force directed upward at 27 ∘ above t
ycow [4]

Answer:

Explanation:

Applied force, F = 18 N

Coefficient of static friction, μs = 0.4

Coefficient of kinetic friction, μs = 0.3

θ = 27°

Let N be the normal reaction of the wall acting on the block and m be the mass of block.

Resolve the components of force F.

As the block is in the horizontal equilibrium, so

F Cos 27° = N

N = 18 Cos 27° = 16.04 N

As the block does not slide so it means that the syatic friction force acting on the block balances the downwards forces acting on the block .

The force of static friction is μs x N = 0.4 x 16.04 = 6.42 N   .... (1)

The vertically downward force acting on the block is mg - F Sin 27°

                                                      = mg - 18 Sin 27° = mg - 8.172    ... (2)

Now by equating the forces from equation (1) and (2), we get

mg - 8.172 = 6.42

mg = 14.592

m x 9.8 = 14.592

m = 1.49 kg

Thus, the mass of block is 1.5 kg.  

6 0
3 years ago
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