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The force involved is = 25200 Newton
Given the values in the questions,
Mass = 1400 kg
Speed or velocity of the car = 27 m/s
Time is given = 1.5 seconds
According to the formula of force,
⇒ Force = Mass x Acceleration
⇒ Force = 1400 x Acceleration ----- equation 1
Now to calculate the value of acceleration we will use,
⇒ Acceleration = (Velocity or Speed) / Time
⇒ Acceleration = 27 / 1.5
⇒ Acceleration = 18 m/
Putting the value of acceleration in equation 1,
⇒ Force = 1400 x 18
⇒ Force = 25200 Newton
Therefore, the force involved is = 25200 Newton
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Answer:
0.72
Explanation:
= Time period of oscillation = 1.5 s
Angular frequency is given as
= Amplitude of oscillation = 40 cm = 0.40 m
= Coefficient of static friction = ?
= acceleration of the block
= mass of the block
Maximum acceleration of the block is given as
frictional force is given as
As per newton's second law