Remember pH is defined as: pH = -log[H+]
so, substituting
4 = - log[H+]
-4 = log [H+] Take antilog of both sides
10^(-4) = [H+]
[H+] = 1 x 10^-4 M
Answer:
Number of moles of strontium chloride = 0.004 mol
Explanation:
Given data:
Molarity = 0.2 M
Volume = 20 mL
Moles of strontium chloride = ?
Solution;
Formula:
Molarity = number of moles of solute / volume in litter
Now we will convert the volume into litter.
20 mL/1000mL × 1 L
0.02 L
Now we will put the values in formula:
Molarity = number of moles of solute / volume in litter
Number of moles of solute = Molarity × volume in litter
Number of moles of solute = 0.2 mol/L × 0.02 L
Number of moles of solute = 0.004 mol
<h3>
Answer: D) all of the above</h3>
Explanation:
The lungs pump oxygen in and carbon dioxide out, which goes through the blood stream to help with the cell's energy needs.
Nutrients pass through the blood stream as well. The nutrients start with the digestive system (mouth, esophagus, stomach, small intestine) before going into the blood stream. The nutrients are building blocks to help make new cells when old ones die off.
When those cells die off, the body sheds them like dead skin, but internal dead cells are passed off as waste. This waste and other byproducts the body doesn't need passes through the blood stream as well.
In short, the blood stream is basically the highway to help get desired materials (eg: oxygen and nutrients) and get rid of waste (eg: carbon dioxide and other unwanted byproducts or dead cell material)
So that's why the answer includes A, B and C.
Answer:
Percentage mass of Tin = 96.3%
Percentage mass of oxygen = 6.40%
Explanation:
The product of the reaction is an oxide of tin.
Assuming all of the 0.500 g sample of tin reacted with oxygen to produce the oxide:
Mass of oxide = 0.534 g
Mass of tin present in the oxide = 0.500 g
Mass of oxygen in the oxide = 0.534 g of oxide - 0.500 g Sn = 0.034 g O
Percentage composition = mass of element/mass of compound × 100%
Percentage composition of Sn = 0.500 g/0.534 g × 100 = 93.6% Sn
Percentage composition of oxygen = 0.034 g/0.534 g × 100 = 6.40%
Answer:
I think the answer is B. the number of students choosing each color.
Explanation:
