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2 years ago

Sq root of 2 minus 1 ÷ sq root of 2 plus 1

Mathematics

1 answer:

elena-s [515]2 years ago

7 0

√2 - 1 (√2 - 1)(√2 - 1)

--------- = ---------------------

√2 + 1 (√2 + 1)(√2 - 1)

2 + 1 - 2√2

= ---------------

2 - 1

= 3 - 2√2 Answer

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I don’t understand how to do this

schepotkina [342]

Answer:

The solution is $x =0.$

Step-by-step explanation:

The equation

$\bold{(1).}\: sin(\dfrac{3\pi }{2} +x)+sin(\dfrac{3\pi }{2} +x) =-2$

can be rewritten as

$2* sin(\dfrac{3\pi }{2} +2) =-2$

and can be further simplified to

$sin(\dfrac{3\pi }{2}+x ) =-1$ .

Now, taking the inverse sine of both sides we get:

$sin^{-1}(sin(\dfrac{3\pi }{2} +x) =sin^{-1}(-1)$

$\bold{(2).}\: \dfrac{3\pi }{2} +2 =sin^{-1}(-1)$

The value of the right side on the interval $[0,2\pi)$ is

$sin^{-1}(-1) = \dfrac{3\pi}{2} \: \:( \text{or }270^o)$ ,

which makes the equation (2)

$\dfrac{3\pi }{2}+x =\dfrac{3\pi}{2}$

solving for $x$ gives

$\boxed{x = 0}$

which is our solution.

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Step-by-step explanation:

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2 years ago

Solve -4 < 3x+2<5.

denis-greek [22]

The answer choice which represents the solution to the inequality as given in the task content is; x>-2 or x≤ 1.

<h3>What is the solution of the give complex inequality?</h3>

On this note, it follows that the inequalities can be solved individually as follows;

-4 < 3x +2

-6 < 3x

x > -2

Also, 3x +2 ≤ 5

3x ≤ 3

x ≤ 1.

Ultimately, the correct answer choice is; Choice C; x>-2 or x≤ 1.