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VMariaS [17]
2 years ago
14

Sq root of 2 minus 1 ÷ sq root of 2 plus 1

Mathematics
1 answer:
elena-s [515]2 years ago
7 0

√2 - 1 (√2 - 1)(√2 - 1)

--------- = ---------------------

√2 + 1 (√2 + 1)(√2 - 1)


2 + 1 - 2√2

= ---------------

2 - 1


= 3 - 2√2 Answer

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I don’t understand how to do this
schepotkina [342]

Answer:

The solution is x =0.

Step-by-step explanation:

The equation

\bold{(1).}\: sin(\dfrac{3\pi }{2} +x)+sin(\dfrac{3\pi }{2} +x) =-2

can be rewritten as

2* sin(\dfrac{3\pi }{2} +2) =-2

and can be further simplified to

sin(\dfrac{3\pi }{2}+x ) =-1.

Now, taking the inverse sine of both sides we get:

sin^{-1}(sin(\dfrac{3\pi }{2} +x) =sin^{-1}(-1)

\bold{(2).}\:  \dfrac{3\pi }{2} +2 =sin^{-1}(-1)

The value of the right side on the interval [0,2\pi) is

sin^{-1}(-1) = \dfrac{3\pi}{2} \: \:( \text{or }270^o) ,

which makes the equation (2)

\dfrac{3\pi }{2}+x  =\dfrac{3\pi}{2}

solving for x gives

\boxed{x = 0}

which is our solution.

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Step-by-step explanation:

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What is the definition of ratio table
Wittaler [7]
A table with columns filled with pairs of numbers that have the same ratio.
4 0
2 years ago
Solve -4 < 3x+2<5.
denis-greek [22]

The answer choice which represents the solution to the inequality as given in the task content is; x>-2 or x≤ 1.

<h3>What is the solution of the give complex inequality?</h3>

On this note, it follows that the inequalities can be solved individually as follows;

-4 < 3x +2

-6 < 3x

x > -2

Also, 3x +2 ≤ 5

3x ≤ 3

x ≤ 1.

Ultimately, the correct answer choice is; Choice C; x>-2 or x≤ 1.

Read more on complex inequality;

brainly.com/question/24761100

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