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OLEGan [10]
3 years ago
8

Physical therapists know as you soak tired muscles in a hot tub, the water will cool down as you heat up. If a 67.9 person at 37

.1 oC immerses in 50.2 kg of water at 40.5o C, the equilibrium temperature is 38.7 oC. What is the specific heat of the person? Use 4.186 kJ/kgoC for the specific heat of water. Answer to 3 significant figures in kJ/kgoC .
Physics
1 answer:
olga55 [171]3 years ago
4 0
Q1=Q2
m1c1(t-t1)=m2c2(t2-t)
67.9kg * c1* (38.7°C-37.1°C)=50.2kg * 4186 J/kg°C * (40.5°C-38.7°C)
67.9kg* c1 * 1.6°C = 50.2kg * 4186 J/kg°C * 1.8°C
108.64 kg°C * c1 = 378246.96 J
c1 = 378246.96J /108.64kg°C
c1=3481.65 J/kg°C
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