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3 years ago

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Two linear polarizing filters are placed one behind the other, so that their transmission directions are parallel to one another

. A beam of unpolarized light of intensity Io is directed at the two filters. What fraction of the light will pass through both filters?a.0.5 Iob.0c.2 Iod.0.25 Ioe. Io

1 answer:

yulyashka [42]3 years ago

7 0

Answer:

a.0.5 Io

Explanation:

The fraction of light passing through the first polarizer will be

$I_1=\frac{I_0}{2}=0.5I_0$

The fraction of light passing through the second polarizer will be

$I_2=0.5I_0cos^2\theta$

where

$\theta$ = Angle between the filters

here, as the transmission directions are parallel to one another

$\theta=0$

$I_2=0.5I_0cos^20\\\Rightarrow I_2=0.5I_0\\\Rightarrow I_2=I_1$

Hence, $0.5I_0$ will pass through both filters

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A reconnaissance plane flies 404 km awayfrom its base at 730 m/s, then flies back to its base at 1095 m/s.What is it’s average s

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The average speed of the plane is 875.999 m/s.

Average speed can be defined as the ratio of total distanced travelled by the object to that of total time taken to cover the distance.

Mathematically, Average speed = Av = $\frac{Total Distance}{Total Time}$

According to the question,

Speed of the plane away from its base V₁ = 730 m/s

Speed of the plane when it flies back V₂ = 1095 m/s

Plane flies the distance D = 404 km

Total Distance covered by the plane S = 404 * 2 km

(because the distance travelled by the plane when going away from the base and then flying back to the base is same)

Therefore S = 808 km = 808 ˣ 10³ m

Time taken by the plane while flying away from the base T₁ = $\frac{D}{V1}$

T₁ = $\frac{404000}{730}$ = 553.425 s

Time taken by the plane while flying back to the base T₂ = $\frac{D}{V2}$

T₂ = $\frac{404000}{1095}$ = 368.949s

Total Time T = T₁ + T₂ = 922.375 s

Therefore Av = $\frac{Total Distance}{Total Time}$

= $\frac{D}{T}$ m/s

= $\frac{808000}{922.375}$ m/s

= 875.999 m/s

The average speed of the plane will be 875.999 m/s.

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1. Who first published the classification of the elements that is the basis of our periodic table today?

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That particular group of elements is reffered to as the "Noble Gasses"--a title that comes from the fact that these gases are very "secure" and don't mix well with other elements.

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Explanation:

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For the two electrons:

$q_1 = q_2 = 1.60\times 10^{-19}\;\text{C}$ .
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Please refer to the image below.

We know from the case, that:

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We know that the moment of inertia for an uniform flat disk is 1/2mr². Then the moment of inertia for the uniform flat disk is:

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Then, the total moment of inertia of the disk with the point mass is:

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