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7nadin3 [17]
3 years ago
11

Two linear polarizing filters are placed one behind the other, so that their transmission directions are parallel to one another

. A beam of unpolarized light of intensity Io is directed at the two filters. What fraction of the light will pass through both filters?a.0.5 Iob.0c.2 Iod.0.25 Ioe. Io
Physics
1 answer:
yulyashka [42]3 years ago
7 0

Answer:

a.0.5 Io

Explanation:

The fraction of light passing through the first polarizer will be

I_1=\frac{I_0}{2}=0.5I_0

The fraction of light passing through the second polarizer will be

I_2=0.5I_0cos^2\theta

where

\theta = Angle between the filters

here, as the transmission directions are parallel to one another

\theta=0

I_2=0.5I_0cos^20\\\Rightarrow I_2=0.5I_0\\\Rightarrow I_2=I_1

Hence, 0.5I_0 will pass through both filters

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I attempted to answer and got 0m, please explain how to get to the answer.
mafiozo [28]

The maximum height to which the ball attain before falling back down is 1147.96 m

<h3>Data obtained from the question</h3>

The following data were obtained from the question:

  • Initial velocity (u) = 150 m/s
  • Final velocity (v) = 0 m/s (at maximum height)
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Maximum height (h) =?

<h3>How to determine the maximum height </h3>

The maximum height reached by the ball can be obtained as illustrated below:

v² = u² – 2gh (since the ball is going against gravity)

0² = 150² – (2 × 9.8 × h)

0 = 22500 – 19.6h

Collect like terms

0 – 22500 = –19.6h

–22500 = –19.6h

Divide both side by –19.6

h = –22500 / –19.6

h = 1147.96 m

Thus, the maximum height reached by the ball is 1147.96 m

Learn more about motion under gravity:

brainly.com/question/22719691

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5 0
1 year ago
Why don't we see other stars during day?
Monica [59]

Answer:

Stars aren't visible during the sunlit hours of daytime because the light-scattering properties of our atmosphere spread sunlight across the sky. Seeing the dim light of a distant star in the blanket of photons from our Sun becomes as difficult as spotting a single snowflake in a blizzard.

Explanation:

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2 years ago
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D) Why is it so difficult to get accurate data for these objects?
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Answer: For what objects? And what data?

Explanation:

5 0
3 years ago
A 5.00-kg object is attached to one end of a horizontal spring that has a negligible mass and a spring constant of 280 N/m. The
lina2011 [118]

Answer:

1) v = 0.45 m/s

2) v = 0.65 m/s

3) v = 0.75 m/s  

Explanation:

1) We can find the speed of the object by conservation of energy:

E_{i} = E_{f}

\frac{1}{2}kx^{2} = \frac{1}{2}kx^{2} + \frac{1}{2}mv^{2}

Where:

k: is the spring constant = 280 N/m

v: is the speed of the object =?

m: is the mass of the object = 5.00 kg

x: is the displacement of the spring

\frac{1}{2}280N/m(0.10 m)^{2} = \frac{1}{2}280N/m(0.08 m)^{2} + \frac{1}{2}5.00 kgv^{2}                              

v = \sqrt{\frac{280N/m(0.10 m)^{2} - 280N/m(0.08 m)^{2}}{5.00 kg}} = 0.45 m/s

2) When the object is 5.00 cm (0.050 m) from equilibrium, the speed of the object is:

\frac{1}{2}kx^{2} = \frac{1}{2}kx^{2} + \frac{1}{2}mv^{2}    

\frac{1}{2}280N/m(0.10 m)^{2} = \frac{1}{2}280N/m(0.05 m)^{2} + \frac{1}{2}5.00 kgv^{2}      

v = \sqrt{\frac{280N/m(0.10 m)^{2} - 280N/m(0.05 m)^{2}}{5.00 kg}} = 0.65 m/s      

 

3) When the object is at the equilibrium position, the speed of the object is:

\frac{1}{2}kx^{2} = \frac{1}{2}kx^{2} + \frac{1}{2}mv^{2}    

\frac{1}{2}280N/m(0.10 m)^{2} = \frac{1}{2}280N/m(0 m)^{2} + \frac{1}{2}5.00 kgv^{2}      

v = \sqrt{\frac{280N/m(0.10 m)^{2}}{5.00 kg}} = 0.75 m/s

I hope it helps you!                                                                                        

8 0
3 years ago
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tresset_1 [31]

In Building, there are a host of protective devices that are installed to protect lives and properties, one of them is the Lightning Conductor that  a metal rod mounted on a structure and intended to protect the structure from a lightning strike. It works on the principle of induction

<h3>Principle of Operation of Lightning Conductor</h3>

The lightning conductor works on the principle of induction:

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Most Lightening conductors are made from copper materials.

Learn about Lightning Conductor:

brainly.com/question/2824044

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