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3 years ago

#2) Solve for side BC, to the nearest whole number. * 1 point 105° A 15

Mathematics

2 answers:

german3 years ago

7 0

Answer:

bro what's the question pls tell

aliina [53]3 years ago

5 0

Yes no yes no yes yes bo yes fjgjgkflldkddoldossooweoodwod jejdkekelew enenekke enekekeke nekdke denne dnde dnd kednkd dnd dje eje enee nee enene

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3 years ago

A concession stand at an athletic event is trying to determine how much to sell cola and iced tea for in order to maximize reven

Cerrena [4.2K]

Solution :

Demand for cola : 100 – 34x + 5y

Demand for cola : 50 + 3x – 16y

Therefore, total revenue :

x(100 – 34x + 5y) + y(50 + 3x – 16y)

R(x,y) = $100x-34x^2+5xy+50y+3xy-16y^2$

$R(x,y) = 100x-34x^2+8xy+50y-16y^2$

In order to maximize the revenue, set

$R_x=0, \ \ \ R_y=0$

$R_x=\frac{dR }{dx} = 100-68x+8y$

$R_x=0$

$68x-8y=100$ .............(i)

$R_y=\frac{dR }{dx} = 50-32x+8y$

$R_y=0$

$8x-32y=-50$ .............(ii)

Solving (i) and (ii),

4 x (i) ⇒ 272x - 32y = 400

(ii) ⇒ (-) 8x - 32y = -50

264x = 450

∴ $x=\frac{450}{264}=\frac{75}{44}$

$y=\frac{175}{88}$

So, x ≈ $ 1.70 and y = $ 1.99

R(1.70, 1.99) = $ 134.94

Thus, 1.70 dollars per cola

1.99 dollars per iced ted to maximize the revenue.

Maximum revenue = $ 134.94

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3 years ago

Hi!! Can you pls help thanks:)

Pani-rosa [81]

1. Y=X-4
2. Y=X*4
3. Y=X+3
4. Y=X/6

8 0

3 years ago