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dusya [7]
3 years ago
12

a sample of salt has 1.74 moles of sodium chloride. how many formula units of the ionic compound are in the sample?

Chemistry
1 answer:
steposvetlana [31]3 years ago
4 0

Answer:

A sample of salt has 1.74 moles of sodium chloride. how many formula units of the ionic compound are in the sample?

Explanation:

Given, 1.74 moles of NaCl.

Since one mole of NaCl consists of --- 6.023 * 10^2^3 formula units.

Then, 1.74mol of NaCl contains how many formula units of NaCl?

1.74 mol x \frac{6.023x10^2^3}{1 mol} \\=10.5x10^2^3formula units.

Hence, the given sample has 10.5x10^23 formula units.

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Which of the following would not be considered matter?<br><br> plants<br> cheese<br> light<br> blood
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Explanation:

Given -

  • An organic compound gives H₂ gas with Na
  • On treatment with alkaline iodine it gives yellow ppt.
  • On oxidation with CrO₃/H⁺ forms an aldehyde (C₂H₄O)

To Find -

  • Name the compound and write the reaction involved

Now,

Let A be the organic compound.

Then,

  1. A + Na → + H₂↑
  2. A + I₂ → CHI₃ (yellow ppt.)
  3. A + CrO₃ + H⁺ → C₂H₄O

Now,

Here we see that compound A reacts with chromic oxide (CrO₃) in the presence of acidic medium gives aldehyde.

  • Functional group of aldehyde = —CHO

And It forms only 2 Carbon aldehyde it means, It is Ethanal (CH₃CHO).

Compound A reacts with chromic oxide (CrO₃) in the presence of acidic medium gives ethanal.

It means,

We know that 1° alcohol on oxidation gives aldehyde.

Here it gives 2 Carbon aldehyde.

It means,

Here 2 Carbon and 1° alcohol is used.

Now,

Its cleared that Compound A is Ethanol.

Reaction Involved -

  1. CH₃CH₂OH + Na → CH₃CH₂O⁻Na⁺ + H₂↑
  2. CH₃CH₂OH + I₂ + OH⁻ → CHI₃↓ + HCOO⁻ + HI + H₂O
  3. CH₃CH₂OH + CrO₃ + H⁺ → CH₃CHO

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