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aksik [14]
3 years ago
14

based on bond energies, what will be the heat of reaction for the formation of 2 moles of hydrogen fluoride from one mole each o

f hydrogen gas and fluorine gas?
Chemistry
1 answer:
juin [17]3 years ago
3 0

Answer:

ΔH₍reaction₎ = ΔH₍ hydrogen gas bond-breakage₎ + ΔH₍fluorine gas bond-breakage₎ + 2.ΔH₍hydrogen fluoride bond-formation₎ .

Explanation:

Reaction:

H₂ + F₂ --> 2.HF      ΔH₍reaction₎

In this reaction, bonds are broken in the hydrogen gas and fluorine gas molecules which then lead to the new bond formation, that is, bond between hydrogen and fluorine atoms which explains the formation of hydrogen fluoride.

ΔH₍reaction₎ = ΔH₍bond-breakage₎ + ΔH₍bond-formation₎

ΔH₍bond-breakage₎ is just ΔH₍ hydrogen gas bond-breakage₎ + ΔH₍fluorine gas bond-breakage₎.

ΔH₍bond-formation₎ is 2.ΔH₍hydrogen fluoride bond-formation₎ .Since the ΔH₍bond-formation₎ is in the units kJ/mol, a factor of 2 comes in the picture

Therefore,

ΔH₍reaction₎ = ΔH₍ hydrogen gas bond-breakage₎ + ΔH₍fluorine gas bond-breakage₎ + 2.ΔH₍hydrogen fluoride bond-formation₎ .

Note: Care should be taken while assigning opposite signs to ΔH₍bond-breakage₎ and ΔH₍bond-formation₎.

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Determine the approximate amount of potassium hydrogen phthalate, KHP, that you will need to neutralize 6.00 ml of 0.100 M NaOH.
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Answer:

potassium hydrogen phthalate KHP MOLAR MASS = 204.233 glmol

to get 1000 ml

Molar concentration = Mass concentration/Molar Mass

mass concentration = molar concentration x molar mass

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so to get 1L

mass conc = 204.233 x 0.1

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if 20.4233g is for 1000ml

then to 6.00 ml

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according to the equation below

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number of moles of NaOH is equal to that of KHP

so the same amount will be needed too, which is

= 0.123g

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