Ask question

Ask question

All categories

3 years ago

8

Pleassse help!!!

1 answer:

11111nata11111 [884]3 years ago

8 0

True

Explanation:

Harry Hess in 1961 resurrected Wegener's continental drift hypothesis and also he mantle convection idea of Arthur Holmes by postulating the theory of sea floor spreading.

After Wegener's postulation of the continental drift hypothesis, not much was done.
It was only around 1931 that Arthur Holmes came up with the idea of a convecting mantle.
After the second world war passed, new instruments were used to investigate and map the ocean floor.
Through this, Arthur Holmes came up with the idea of a spreading sea floor.
This gave a full gleam picture to the idea of a moving earth and the more accepted terminology of "Plate tectonics " came to the fore.

Learn more:

Sea floor spreading brainly.com/question/9912731

Continental drift brainly.com/question/5002949

#learnwithBrainly

You might be interested in

What is the molar mass of C4H10

Phantasy [73]

Your answer would be 58.12g/mol ;)

7 0

3 years ago

Calculate the Molarity when a 6.11 mL solution of 0.1 H2SO4 is diluted with 105.12 mL of water

barxatty [35]

Molarity after dilution : 0.0058 M

<h3>Further explanation </h3>

The number of moles before and after dilution is the same

The dilution formula

M₁V₁=M₂V₂

M₁ = Molarity of the solution before dilution

V₁ = volume of the solution before dilution

M₂ = Molarity of the solution after dilution

V₂ = Molarity volume of the solution after dilution

M₁=0.1 M

V₁=6.11

V₂=105.12

$\tt M_2=\dfrac{M_1.V_1}{V_2}=\dfrac{0.1\times 6.11}{105.12}=0.0058~M$

5 0

3 years ago

What is the difference between hydrophilic and hydrophobic?

Nataliya [291]

Hydrophilic - attracted to water
Hydrophobic - resists water

7 0

2 years ago

HELP ASAP ILL GIVE BRAINLIEST!!

Dahasolnce [82]

Of course we would experience them.

3 0

2 years ago

Calculate the change in entropy when 1.00 kg of water at 100 ∘C is vaporized and converted to steam at 100 ∘C. Assume that the h

andrew11 [14]

Answer : The change in entropy is $6.05\times 10^3J/K$

Explanation :

Formula used :

$\Delta S=\frac{m\times L_v}{T}$

where,

$\Delta S$ = change in entropy = ?

m = mass of water = 1.00 kg

$L_v$ = heat of vaporization of water = $2256\times 10^3J/kg$

T = temperature = $100^oC=273+100=373K$

Now put all the given values in the above formula, we get:

$\Delta S=\frac{(1.00kg)\times (2256\times 10^3J/kg)}{373K}$

$\Delta S=6048.25J/K=6.05\times 10^3J/K$

Therefore, the change in entropy is $6.05\times 10^3J/K$

5 0

2 years ago