Pleassse help!!!

Chemistry

1 answer:

11111nata11111 [884]3 years ago

8 0

True

Explanation:

Harry Hess in 1961 resurrected Wegener's continental drift hypothesis and also he mantle convection idea of Arthur Holmes by postulating the theory of sea floor spreading.

After Wegener's postulation of the continental drift hypothesis, not much was done.
It was only around 1931 that Arthur Holmes came up with the idea of a convecting mantle.
After the second world war passed, new instruments were used to investigate and map the ocean floor.
Through this, Arthur Holmes came up with the idea of a spreading sea floor.
This gave a full gleam picture to the idea of a moving earth and the more accepted terminology of "Plate tectonics " came to the fore.

Learn more:

Sea floor spreading brainly.com/question/9912731

Continental drift brainly.com/question/5002949

#learnwithBrainly

You might be interested in

If there are 1.55 x 1024 molecules of hydrogen peroxide (H2O2), what is the mass of the sample?

bezimeni [28]

Answer:

87.54 g of H₂O₂

Explanation:

From the question given above, the following data were obtained:

Number of molecules = 1.55×10²⁴ molecules

Mass of H₂O₂ =.?

From Avogadro's hypothesis,

6.02×10²³ molecules = 1 mole of H₂O₂

Next, we shall determine the mass of 1 mole of H₂O₂. This can be obtained as follow:

1 mole of H₂O₂ = (2×1) + (2×16)

= 2 + 32

= 34 g

Thus,

6.02×10²³ molecules = 34 g of H₂O₂

Finally, we shall determine mass of H₂O₂ that contains 1.55×10²⁴ molecules. This can be obtained as follow:

6.02×10²³ molecules = 34 g of H₂O₂

Therefore,

1.55×10²⁴ molecules

= (1.55×10²⁴ × 34)/6.02×10²³

1.55×10²⁴ molecules = 87.54 g of H₂O₂

Thus, 87.54 g of H₂O₂ contains 1.55×10²⁴ molecules.

8 0

2 years ago

How much of a 1.00 mg sample of americium remains after 3 half-lives?

notka56 [123]

Answer: 0.125mg americium

Half-lives is a set of duration when a sample will become half of their original mass. In this case, the initial mass is 1mg and the sample is going for 3 times half-lives. Then the calculation would be: 1mg $1/2^{3}$ = 1/8 mg= 0.125mg.