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Karo-lina-s [1.5K]
3 years ago
13

Consider a standard room thermostat. Determine the sensor, transducer, output, and control stages for this measurement system.

Engineering
1 answer:
Anni [7]3 years ago
3 0

Answer:

Sensor/transducer: bimetallic thermometer

Output: displacement of thermometer tip

Control Tstages: mercury contact switch (open:furnace off; closed:furnace on

Explanation:

for a standard room thermostat : This is the device that sets/determines the temperature of an enclosure.

Sensor/transducer: bimetallic thermometer: Bimetalic thermometer are used for measuring the temperature of the ambient air . bimetallic thermometer actually contains two metals. they undergo linear expansivity as the temperature of the room changes.in other words, they experience contraction and expansion with increase or decrease in temperature.The sensor is basically coupled with a transducer which turns the measured variable(Temperature)  into something else, such as a movement on a dial or an electrical signal

Output: displacement of thermometer tip

Controller: mercury contact switch (open:furnace off; closed:furnace on)

once the contact switch is open the furnace can go off. when the contact switch is closed, the furnace will come up.

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Explanation:

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where

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Velocity is proportional to square root of head under which the flow occurs.

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A continuous random variable, X, whose probability density function is given by f(x) = ( λe−λx , if x ≥ 0 0, otherwise is said t
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Answer:

a) F(x) = \lambda \int_0^{\infty} e^{-\lambda x} dx= -e^{-\lambda x} \Big|_0^{\infty} = 1- e^{-\lambda x} \

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Explanation:

Previous concepts

The cumulative distribution function (CDF) F(x),"describes the probability that a random variableX with a given probability distribution will be found at a value less than or equal to x".

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Let X the random variable of interest. We know on this case that X\sim Exp(\lambda)

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f(x) = \lambda e^{-\lambda x} , x\geq 0

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F(x) = \lambda \int_0^{\infty} e^{-\lambda x} dx= -e^{-\lambda x} \Big|_0^{\infty} = 1- e^{-\lambda x} \

Part b

Assuming that X \sim Exp(\lambda =0.1), then the density function is given by:

f(x) = 0.1 e^{-0.1 x} dx , x\geq 0

And for this case we want this probability:

P(10 < X

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P(10 < X

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Explanation:

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