Answer:
1.0MG
Explanation:
to solve this problem we use this formula
S₀-S/t = ksx --- (1)
the values have been given as
concentration = S₀ = 250mg
effluent concentration = S= 10mg
value of K = 0.04L/day
x = 3000 mg
when we put these values into this equation,
250-10/t = 0.04x10x3000
240/t = 1200
we cross multiply from this stage
240 = 1200t
t = 240/1200
t = 0.2
remember the question says that 5MGD is required to be treated
so the volume would be
v = 0.2x5
= 1.0 MG
you face is A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.
An alpha-numeric designator which is systematically assigned at the time of manufacture, so as to identify the manufacturer, month, year, location, and batch is referred to as lot number.
<h3>What is a product?</h3>
A product can be defined as any physical object (tangible item) that is typically produced by a manufacturer so as to satisfy and meet the demands, needs or wants of every customer. Also, some examples of a product include the following:
- Refrigerator
- Television
- Microwave oven
- Pencil
- Smartphone
- Computer
- Perfume
<h3>What is lot number?</h3>
A lot number can be defined as an alpha-numeric designator which is systematically designed and assigned at the time of manufacture, so as to identify the manufacturer, month, year, location, and batch.
Read more on products here: brainly.com/question/14308690
#SPJ1
Answer:
Qcd=0.01507rad
QT= 0.10509rad
Explanation:
The full details of the procedure and answer is attached.
Answer:
the difference in pressure between the inside and outside of the droplets is 538 Pa
Explanation:
given data
temperature = 68 °F
average diameter = 200 µm
to find out
what is the difference in pressure between the inside and outside of the droplets
solution
we know here surface tension of carbon tetra chloride at 68 °F is get from table 1.6 physical properties of liquid that is
σ = 2.69 × 
N/m
so average radius = 
= 100 µm = 100 ×
m
now here we know relation between pressure difference and surface tension
so we can derive difference pressure as
2π×σ×r = Δp×π×r² .....................1
here r is radius and Δp pressure difference and σ surface tension
Δp = 
put here value
Δp = 
Δp = 538
so the difference in pressure between the inside and outside of the droplets is 538 Pa
