Question

A mass of 0.3 kg is suspended from a spring of stiffness 0.4 N/mm. The damping is 3.286335345 kg/s. What is the undamped natural frequency of the system in Hz?

Answer 1

Answer:

 f=5.81 Hz

Explanation:

Given that

m= 0.3 kg

K= 0.4 N/mm

K= 400 N/m

C= 3.28

We know that undamped natural frequency given as

$\omega= \sqrt{\dfrac{K}{m}}$

Now by putting the values

$\omega= \sqrt{\dfrac{K}{m}}$

$\omega= \sqrt{\dfrac{400}{0.3}}$

  ω = 36.51 rad/s

We know that

ω = 2 π f

36.51 = 2 x π x f

f=5.81 Hz

So the undamped natural frequency is 5.81 Hz.