Answer:
True
Explanation:
Actually this are some of the nitty gritty answers and ways to control or stip stress, lemme explain them you see stress most of the time may come from deep thoughts that are and are pushing you to the wall, and you in your state you as you react to that which is so demanding as it makes you tense,so if at you will incorporate physical activities like running, jogging or push ups the psychological tension in you is broken as you focus so much on the activities rather than the tension, then getting enough rest cools the mind and all your thoughts settle as in your brain starts to adapt to chilling and relaxation and enough sleep will actually make ones head to be at peace because if you lack enough sleep you might have an excruciating migraine when you are stressed up and finally relaxation techniques makes the body accept the situation and then you manouver out of it as you grow strongly.
Hope this will help!
Answer:
The FEM is a general numerical method for solving partial differential equations in two or three space variables (i.e., some boundary value problems). To solve a problem, the FEM subdivides a large system into smaller, simpler parts that are called finite elements.
Answer:
Minimum Allowable diameter for each of the 5 bolts = 0.0394 m = 3.94 cm
Explanation:
Maximum Working Stress = Ultimate Shear Stress/factor of safety
Maximum Working Stress = 280 MPa/3.8 = 73.68 MPa
Working Stress = Applied load/Minimum allowable Area = L/A
Minimum Allowable Area = Applied Load/Maximum Working Stress
A = 450000/73680000 = 0.00611 m²
This area is supplied by 5 bolts, so each bolt supplies A/5 = 0.0061/5 = 0.00122 m²
Cross sectional Area of bolts = πD²/4
0.00122 = πD²/4
D² = 4 × 0.00122/π = 0.00155
D = √0.00155 = 0.0394 m = 3.94 cm
Each of the five bolt can have a minimum diameter of 3.94 cm
Hope this Helps!!!
Answer:
Explanation:
Before: PT= 0.10, PB= 0.03 (given) ET = 2.5 ER = 2.0 (Table 6.5)
fHV= 0.847 (Eq. 6.5) PHF = 0.95, fp= 0.90, N=2, V = 2200 (given)
vp= V/[PHF⋅fHVTB⋅fp⋅N] = 1518.9 (Eq. 6.3)
BFFS = 50+5, BFFS =55 (given) fLW= 6.6
TLC=6+3=9 fLC= 0.65
fM= 0.0
fA= 1.0
FFS = BFFS −fLW−fLC–fM–fA= 46.75 (Eq. 6.7)
Use FFS=45 D= vp/S = 33.75pc/mi/ln Eq (6.6)
After: fA= 3.0
FFS = BFFS −fLW−fLC–fM–fA= 44.75 (Eq. 6.7)
Use FFS=45 Vnew= 2600 Vp= Va/[PHF⋅fHB⋅fp⋅N] = 1795 (Eq. 6.3) D= vp/S = 39.89pc/mi/ln
