Answer:
minimum radius of bend.
Explanation:
The sharpest bend that can be placed in a piece of metal without critically weakening the part is called the minimum radius of bend.
Answer:
Evaluate the required thickness of styrofoam for the freezer compartment in the previous problem when the inside wall is exposed to air at -10°C through a surface coefficient of 16 W/m2 · K and the outer wall is exposed to 33°C air with a surface coefficient of 32 W/m2 · K. Determine the surface temperatures for this situation.
Explanation:
Answer:
4.18 J/KgK
Explanation:
Equilibrium point is reached when
m₁*c₁(T₁-T) = m₂*c₂(T -t₂)
m1 = 20
c1 = 0.5
T1 = 450
m2 = 150 kg
c2 = 2.6
T2 = 50
putting these values into the formula
20*0.5 (450-T) = 150*2.6(T - 50)
4500 - 10T = 390T<em> - 19500</em>
4500 + 19500 = 390T + 10T
24,000 = 400T
T = 24000/400
= 60⁰C
ΔSmetal = m1*c1In[t + 273]/[T1+273]
= 20*0.5 In (60+273)/450+273
= 10 ln(333/723)
= 10 * -0.7752
= -7.752
ΔS/oil =
m2*s2(60 + 273)/50 + 273)
= 150*2.6ln(333/323)
= 390 * 0.03048
= 11.88j/KgK
Δ<em>total = -7.7+11.8</em>
<em>= </em><em>4.18J/KgK</em>
this is the enthropy change
Answer:
You can use the following code in order to generate the odd and even lists separately:
def splitOddEven(number_list):
"""it separate a list of numbers into odd and even"""
odd_list = [];
even_list = [];
while(number_list):
current_number = number_list.pop();
if(current_number % 2 == 0):
even_list.append(current_number)
else:
odd_list.append(current_number)
return (even_list, odd_list)
test_list = [2,3,1,5,78,32,121,12]
even, odd = splitOddEven(test_list[:])
print("These are the even numbers of your list:" + str(even))
print("\nThese are the odd numbers of your list: " + str(odd))
Explanation:
