Answer:
Pumps converts mechanical energy into hydraulic energy while turbines convert hydraulic energy into mechanical energy.
Explanation:
The machines which converts and transfers mechanical energy in the form of torque on the shaft into hydraulic energy in the form of water under pressure are called pumps whereas those machines which converts water pressure or hydraulic energy into mechanical energy that is further converted into electrical energy are called turbines.
The pump impeller rotates in the opposite direction to the turbine runner.
A turbine delivers work as output whereas a pump consumes work.
First law of thermodynamics for a pump :
W = ( H₁-H₂) +Q , where H₁ > H₂
First law of thermodynamics for a turbines :
W = ( H₂-H₁) +Q , where H₁ < H₂
Answer:
That there is a grounded winding
Explanation:
When the ohm meter is set to the maximum range, and a meter lead is placed on the compressor casing. A reading of any value on the ohm meter is an indication that the winding is grounded in which case it would be necessary to change the compressor
The compressor terminals are covered with a shroud making it difficult to take measurements. To make it easier, the plug can extended with an extension wire.
Answer:
True
Explanation:
The fundamental steps involved in the operation of a solar cell are as follows:
- Light is incident on the solar cell and this light energy is absorbed by the solar cell.
- The absorbed energy results in the movement of the electron inside the cell which constitutes the electric current in the cell.
- Electric current flows and electricity is produced.
- Hence,in solar cell the light energy is responsible for the only voltage in the cell.
Where’s the illustration?
The radius of the specimen is 60 mm
<u>Explanation:</u>
Given-
Length, L = 60 mm
Elongated length, l = 10.8 mm
Load, F = 50,000 N
radius, r = ?
We are supposed to calculate the radius of a cylindrical brass specimen in order to produce an elongation of 10.8 mm when a load of 50,000 N is applied. It is necessary to compute the strain corresponding to this
elongation using Equation:
ε = Δl / l₀
ε = 10.8 / 60
ε = 0.18
We know,
σ = F / A
Where A = πr²
According to the stress-strain curve of brass alloy,
σ = 440 MPa
Thus,
Therefore, the radius of the specimen is 60 mm