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Find the duration
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Time : 9:00am to 10:15am
Duration: 1hour 15 mins or 1.25hours
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Find difference in distance travelled between the two cyclists.
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Difference in speed = 6km/h
1 hour = 6 km
1.25 hours = 7.5km
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Find the distance the cyclist traveled
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42.5 - 7.5 = 35km
35km ÷ 2 = 17.5km
The slower cyclist traveled 17.5 km in the 1.25 hours
17.5 + 7.5 = 25 km
The faster cyclist traveled 25km in the 1.25 hours
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Find the speed of the slower cyclist
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1.25 hour = 17.5 km
1 hour = 17.25 ÷ 1.25
1 hour = 14km
The cyclist was traveling at 14km/h
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Find the speed of the faster cyclist
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1.25 hour = 25km
1 hour = 25 ÷ 1.25
1hour = 20 km
The cyclist was traveling at 20km/hour
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Answer: The speed were 14km/h and 20 km/h
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Let the number of large bookcases be x and number of small bookcases be y, then
Maximise P = 80x + 50y;
subkect to:
6x + 2y ≤ 24
x, y ≥ 2
The corner points are (2, 2), (2, 6), (3.333, 2)
For (2, 2): P = 80(2) + 50(2) = 160 + 100 = 260
For (2, 6): P = 80(2) + 50(6) = 160 + 300 = 460
For (3.333, 2): P = 80(3.333) + 50(2) = 266.67 + 100 = 366.67
Therefore, for maximum profit, he should produce 2 large bookcases and 6 small bookcases.
The graph of the function contains the points (0,-7), (1,-9), and (3,-1) is incorrect
it contains all the points except the last set...(3,-1)
y = -2x - 7
-1 = -2(3) - 7
-1 = -6-7
-1 = - 13 (incorrect)
Answer:
3
______
4 | 12
-12
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0
Step-by-step explanation:
12/4
The top number always goes inside (larger or not), and the bottom number always goes on the outside (larger or not).
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4 | 12
Ask yourself how many 4's are in 12.
Let's see one 4 is just 4.
We can probably do more 4's than that.
Two 4's gives us 4+4=8.
Let's see if we can put one 4 in there.
Three 4's gives us 4+4+4=12.
So we can fit three 4's into 12 and there is nothing left over.
3
______
4 | 12
-12 (since 4 times 3 or 4+4+4 is 12)
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0
Answer:Please include images of the graphs!
