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Gre4nikov [31]
3 years ago
10

A solution of HNO3 has a [H+] concentration of 0.001 M. What is the pH of point

Chemistry
1 answer:
Citrus2011 [14]3 years ago
7 0

Answer:

3

Explanation:

pH=-log(H+)

- Hope that helps! Please let me know if you need further explanation.

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What is Sublimation? ​
Stolb23 [73]

Answer:

When a solid turns to a gas.

Explanation:

4 0
3 years ago
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Let’s say you have 3 UV active spots in the crude material and co-spot TLC plate. One has the same Rf value as the starting mate
Troyanec [42]

Answer:

Answer: (1R,2S) / (1S, 2R) , (1R,2R) / (1S, 2S)  

Explanation:

Sodium borohydride reduction of benzoin will give four possible stereo isomers out of which are (1R,2S) - (1S, 2R) isomers and (1R,2R) - (1S, 2S) isomers which are known as enantiomers.

In general enantiomers show single spot in the TLC as they do not show any difference in Rf value (i.e) (1R,2S) - (1S, 2R) isomers show only one spot although they are two compounds and also (1R,2R) - (1S, 2S) isomers also show one spot. That is the reason why you are observing two spots in the TLC ( of reaction mixture) other than starting materilal.

8 0
3 years ago
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What is the de broglie wavelength of a 0.17-kg hockey puck moving at 37 m/s ?
Stolb23 [73]
Im taking lambda as x (wavelength)

m = 0.17 kg

v=37m/s

h=6.62*10^-34m²kg/s

x= h/mv


x = 6.62 \times 10 ^{ - 34}  \div 0.17 \times 37
x =1.05 \times {10}^{ - 34}  m
5 0
3 years ago
Fill in the Blank Question
creativ13 [48]

Answer:

Protons

Explanation:

It's the number of protons in the nucleus of an atom, which determines the chemical properties of an element and its place in the periodic table.

Hope this helped, can I also get brainliest plz?

7 0
2 years ago
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Given the unbalanced equation below, answer the following: Calculate the number of liters of 3.00 M lead (II) iodide solution pr
mr_godi [17]

The number of liters of 3.00 M lead (II) iodide : 0.277 L

<h3>Further explanation</h3>

Reaction(balanced)

Pb(NO₃)₂(aq) + 2KI(aq) → 2KNO₃(aq) + PbI₂(s)

moles of KI = 1.66

From the equation, mol ratio of KI : PbI₂ = 2 : 1, so mol PbI₂ :

\tt \dfrac{1}{2}\times 1.66=0.83

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

\large \boxed {\bold {M ~ = ~ \dfrac {n} {V}}}

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

So the number of liters(V) of 3.00 M lead (II) iodide-PbI₂ (n=0.83, M=3):

\tt V=\dfrac{n}{M}\\\\V=\dfrac{0.83}{3}\\\\V=0.277~L

5 0
3 years ago
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