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LekaFEV [45]
3 years ago
12

Can cars stop on a dime? Calculate the acceleration of a 1400 kg car if it can stop from 35 km/h on a dime (diameter= 1.7 cm) ho

w many g’s is this?
Physics
1 answer:
Deffense [45]3 years ago
6 0

Answer:

The acceleration of the cart is 283.54g

Explanation:

It is given that,

Initial speed of the car, u = 35 km/h = 9.72 m/s

Finally, it stops, v = 0

Diameter of the dime, d = 1.7 cm

Let a is the acceleration of the car. Using third equation of motion to find it as :

v^2-u^2=2ad

-u^2=2ad

a=\dfrac{-u^2}{2d}

a=-\dfrac{(9.72)^2}{2\times 1.7\times 10^{-2}}

a=-2778.77\ m/s^2

So, the acceleration of the car is 2778.77\ m/s^2 and it is decelerating.

Since, g=9.8\ m/s^2

So, a=\dfrac{2778.77}{9.8}=283.54\ g

So, the acceleration of the cart is 283.54g. Hence, this is the required solution.

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san4es73 [151]

Answer:

B

Explanation:

F = ma

500N = 200 × a

200a. = 500N

a. =. 500N/200

a. =. 2.5m/s²

PLEASE GIVE BRAINLIEST.

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3 years ago
the cycle of the moon through its phases, or the synodic month, is a. 21 days long. b. 27 1/3 days long. c. 29 1/2 days long. d.
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Obtenha a velocidade escalar média, em cada caso:
Liono4ka [1.6K]
Hahahahha ok it’s B or C or it B
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A 2 kg ball is moving 3 m/s when it starts rolling up a hill.
AURORKA [14]

Answer:

the height reached is = 0.458 [m]

Explanation:

We need to make a sketch of the ball and see the location of the reference point where the potential energy is zero. But the kinetic energy will be defined by the following expression:

Ek=\frac{1}{2} *m*v^{2} \\where:Ek= kinetic energy [J]\\m = mass of the ball [kg]\\v = velocity of the ball [m/s]

Replacing the values on the equation we have:

Ek=\frac{1}{2}*(2)*(3^{2} )\\ Ek=9[J]\\

This kinetic energy will be transformed in potential energy in the moment when the ball starts to rolling up. Therefore the maximum height reached by the ball depends of the initial velocity given to the ball.

Ek=Ep\\where\\Ep=potential energy [J]\\Ep=m*g*h\\where\\g=gravity = 9.81[m/s^2]\\h=height reached [m]\\

Now we have:

h=\frac{Ep}{m*g} \\h=\frac{9}{2*9.81} \\\\h=0.45 [m]

In that moment when the ball reach the 0.45 [m] the potencial energy will be maximum and equal to the kinetic energy when the ball has a velocity of 3[m/s]

6 0
3 years ago
Which particles contribute to the net charge and how does each change the net charge?
Licemer1 [7]

The two subatomic particles that contribute to the net charge of an ion are electrons and protons.

<h3>What is an atom?</h3>

Atom is the smallest possible amount of matter which still retains its identity as a chemical element, now known to consist of a nucleus surrounded by electrons.

The atom is made up of three components called subatomic particles as follows;

  • Protons
  • Electrons
  • Neutrons

The proton is the positively charged subatomic particle forming part of the nucleus of an atomwhile the electron is the subatomic particle having a negative charge and orbiting the nucleus.

This suggests that the two subatomic particles that contribute to the net charge of an ion are electrons and protons. That is;

Net charge = protons - electrons

Learn more about subatomic particles at:brainly.com/question/13303285

#SPJ1

3 0
2 years ago
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