Answer:
A coil of wire is connected to a power supply, and a current runs in the coil. A single loop of wire is located near the coil, with its axis on the same line as the axis of the coil. The radius of the loop is 3 cm. At time t1 the magnetic field at the center of the loop, due to the coil, is 0.9 T, in the direction shown in the diagram; the current in the coil is constant.(a) What is the absolute value of the magnetic flux through the loop at time t1? mag = (No Response) 0.00254 T m2 (b) What approximations or assumptions did you make in calculating your answer to part (a)? Check all that apply. The magnetic field due to the coil is uniform in direction over the area of the loop.The magnetic field outside the loop is zero. The magnitude of the magnetic field due to the coil is uniform over the area of the loop.(c) What is the direction of the induced "curly" electric field inside the wire of the loop at time t1? (Remember that at this time the current in the coil is constant.)(No Response) E = 0 At a later time t2, the current in the coil begins to decrease. (d) Now what is the direction of the induced "curly" electric field in the loop?(No Response) counter-clockwise At time t2 the rate of change of the magnetic field at the center of the loop, due to the coil, is -0.25 T/s.
e) At this time, what is the absolute value of the rate of change of the magnetic flux through the loop?|dmag/dt| = (No Response) 0.000707 T m2/s(f) At this time, what is the absolute value of the emf in the loop?|emf| = (No Response) 0.000707 V(g) What is the magnitude of the electric field at location P, which is inside the wire? || = (No Response) 0.00375 V/m (h) Now the wire loop is removed. Everything else remains as it was at time t2; the magnetic field is still changing at the same rate. What is the magnitude of the electric field at location P?|| = (No Response) 0.00375 V/m
The surface of the rock eroded
1.)Multi-cellular
2.)Organism
3.)Cells
4.)Uni-cellular
5.)Homeostasis
6.)Reproduction
7.)Response
8.)Stimulus
9.)Energy
10.)Photosynthesis
11.)Plants
12.)Glucose
13.)Reproduction
I pretty sure these are correct,
Hope this helps
Answer:
the red pointer on the magnet ( grey region) : points towards north
red pointer outside the magnet ( white region) is pointing towards south
Explanation:
please see the attached image
Answer:
ar = 5.86*10^-3 m/s^2
Explanation:
In order to calculate the radial acceleration of the Earth, you first take into account the linear speed of the Earth in its orbit.
You use the following formula:
(1)
G: Cavendish's constant = 6.67*10^-11 m^3 kg^-1 s^-2
Ms: Sun's mass = 1.98*10^30 kg
r: distance between Sun ad Earth = 1.50*10^8 km = 1.50*10^11 m
Furthermore, you take into account that the radial acceleration is given by:
(2)
You replace the equation (1) into the equation (2) and replace the values of all parameters:
The radial acceleration of the Earth, towards the sun is 5.86*10^-3 m/s^2
