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3 years ago

The right answer can you help me plz

Mathematics

1 answer:

MArishka [77]3 years ago

6 0

sooooooo....whats the question???

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Find the surface area of the prism.<br> 7 yd<br> 7 yd<br> 7 yd

AlexFokin [52]

Answer:

343 yd

Step-by-step explanation:

4 0

3 years ago

Write the equation of a line perpendicular to y=3x+1and goes through the point ( 6,2) y=−13x+4 y=−13x−4 y=3x+4 y=3x−4

Korolek [52]

Answer:

$y=-\frac{1}{3}x+4$

Step-by-step explanation:

step 1

Find the slope of the perpendicular line

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal

(the product of their slopes is equal to -1)

In this problem

we have

$y=3x+1$

The equation of the given line is $m=3$

the slope of the perpendicular line to the given line is

$m=-\frac{1}{3}$

step 2

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

we have

$m=-\frac{1}{3}$

$(x1,y1)=(6,2)$

substitute

$y-2=-\frac{1}{3}(x-6)$

Convert to slope intercept form

$y=mx+b$

Distribute right side

$y-2=-\frac{1}{3}x+2$

$y=-\frac{1}{3}x+2+2$

$y=-\frac{1}{3}x+4$

6 0

3 years ago

What is the standard form of y=(x-4)^2-6

Ahat [919]

Answer:

standard form : 2x + y = -2

8 0

3 years ago

lukranit [14]

Answer:

Step-by-step explanation:

The y-coordinate of the point where both lines intersect will give us the same solution for x.

At y = 4, both equations will have a corresponding x-value of 1.

Therefore, the value of y that that will make both equations have the same solution of x is 4.

7 0

3 years ago

The differential equation in Example 3 of Section 2.1 is a well-known population model. Suppose the DE is changed to dP dt = P(a

LuckyWell [14K]

Answer:

Decreases

Step-by-step explanation:

We need to determine the integral of the DE;

$dP/dt=P(aP-b)$

$dP=P(aP-b)dt$

$1/(dP^2-bP)dP=dt$

We can solve this by integration by parts on the left side. We expand the fraction 1/P²:

$1/(d-b/P)\cdot{P^2} dP$

let

$u=d-b/P$

$du/dP=b/P^2$

$dP=$ $\int\limits {P^2/b} \, du$

$P=lnu/b$

Substitute u in:

$P=ln(d-b/P)/b$

Therefore the equation is:

$ln(d-b/P)/b=t$

We simplify:

$d-b/P=e^b^t$

$P=b/(d-e^b^t)$

As t increases to infinity P will decrease

6 0

3 years ago