What name is given to the property of an object to resist changes in motion

A cart moves along a track at a velocity of 3.5 cm/s. When a force is applied to the cart, its velocity increases to 8.2 cm/s. I

Lorico [155]

Answer:

3.13cm/s²

Explanation:

Given

Initial velocity u = 3.5cm/s

Final velocity v = 8.2cm/s

Time t = 1.5secs

Required

Acceleration of the cart a

To get that, we will use the equation of motion

v = u+at

Substitute the given parameters

8.2 = 3.5+1.5a

1.5a = 8.2-3.5

1.5a = 4.7

a = 4.7/1.5

a = 3.13cm/s²

Hence the acceleration to the cart is 3.13cm/s²

3 0

3 years ago

A submarine is 2.99 ✕ 102 m horizontally from shore and 1.00 ✕ 102 m beneath the surface of the water. A laser beam is sent from

Vsevolod [243]

Answer:

a The diagram of the situation is shown on the first uploaded image

b the angle of incidence beam striking the water is $\theta = 49.63^o$

c the angle of refraction beam striking the water is $r = 59.7^o$

d The angle the refracted beam make with respect to the horizontal is $= 30.3^o$

e The height of the target above sea level is

$h= 125.05m$

Explanation:

From the diagram we see that the angle of the beam striking the water is

$tan \theta = \frac{100}{85}$

$\theta = tan^{-1}(\frac{100}{85} )$

$= 49.63^o$

According to Snell's law

$\mu_{water} *sin(i) = \mu_{air} *sin(r)$

Where $\mu_{water }$ is the refractive index of water = 1.333

$i$ is the angle of incidence

$\mu_{air}$ is the refractive index of air = 1

r is the angle of refraction

Substituting values accordingly

$1.33 * sin (40.37) = 1 * sin(r)$

Making r the subject of the formula

$r = sin^{-1}(\frac{1.333 *sin(40.37)}{1})$

$= 59.7^o$

looking at the diagram we can see that to obtain the angle the refraction beam makes with the horizontal by subtracting the angle refraction from 90°

i.e $90 -59.7 = 30.3$ °

From the diagram we see that the height target above sea level can be obtained by this relation

$tan \theta = \frac{h}{214}\\$

Where h is the is the height

$tan(30.3) = \frac{h}{214}$

$h = 214 * tan (30.3)$

$=125.05m$

4 0

3 years ago

What kind of relationship exists between sound and the temperature of material

KATRIN_1 [288]

speed increases with temp maybe

8 0

3 years ago

A 2 column table with 2 rows. The first column is labeled material with entries gold, iron. The second column is labeled specifi

topjm [15]

Iron atoms are heavier than gold atoms

Explanation:

Chart:

Materials Specific heat

Gold 0.129

Iron 0.45

The specific heat of a substance is the amount of heat required to raise the temperature of 1g of the substance by 1K.

We can see that the more the mass of a substance, the higher the specific heat needed to raise the temperature.

Specific heat is directly proportional to the mass of substance.

It also dependent on the amount of heat supplied and the nature of the substance.

The mass of a body is the amount of substance it contains.
A heavier substance has more number of atoms in it.
Since iron has a higher specific it, the atoms must be heavier or more than that of gold.

learn more:

Specific heat brainly.com/question/7210400

#learnwithBrainly

8 0

4 years ago

Read 2 more answers

A chamber fitted with a piston contains 1.90 mol of an ideal gas. Part A The piston is slowly moved to decrease the chamber volu

yarga [219]

Answer:

The work done is 5136.88 J.

Explanation:

Given that,

n = 1.90 mol

Temperature = 296 K

If the initial volume is V then the final volume will be V/3.

We need to calculate the work done

Using formula of work done

$W=nRT\ ln(\dfrac{V_{f}}{V_{i}})$

Put the value into the formula

$W=1.90\times8.314\times296\ ln(\dfrac{\dfrac{V}{3}}{V})$

$W=1.90\times8.314\times296\ ln(\dfrac{1}{3})$

$W=−5136.88\ J$

The Work done on the system.

Hence, The work done is 5136.88 J.

5 0

3 years ago