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3 years ago

Please help me .finish this paper

Physics

1 answer:

Evgesh-ka [11]3 years ago

7 0

Solution-1:-

$\boxed{\sf \dfrac{10\times 1000}{60\times 60}}$

Solution:-2

$\boxed{\sf Sodium\:and\:Potassium}$

Solution:-3

$\boxed{\sf 320m}$

Solution:-4

$\boxed{\sf Rough\:tiles\:are\:used\:in\:bathroom}$

Solution:-5

$\boxed{\sf Mg_3N_2}$

Solution:-6

$\boxed{\sf Grapes\:and\:Rambutan}$

Solution:-7

$\boxed{\sf {}^{}_{}N}$

Solution:-8

$\boxed{\sf Galactuse}$

Solution:-9

$\boxed{\sf Y-X}$

Solution:-10

$\boxed{\sf Cell\:wall}$

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PLEASE HELP!!!!

s2008m [1.1K]

You can download answer here

tinyurl.com/wpazsebu

4 0

3 years ago

Fill in the blank. _______________, not velocity, is used to calculate the average acceleration.

Ainat [17]

Explanation:

Calculating acceleration is complicated if both speed and direction are changing or if you want to know acceleration at any given instant in time. However, it’s relatively easy to calculate average acceleration over a period of time when only speed is changing. Then acceleration is the change in velocity (represented by Δv) divided by the change in time (represented by Δt):

acceleration=ΔvΔt

8 0

3 years ago

Read 2 more answers

A rock of mass m is twirled on a string in a horizontal plane. The work done by the tension in the string on the rock is..

anyanavicka [17]

Answer:

work done by tension force on the twirled stone must be ZERO always

Explanation:

As we know that work done by a force on an object is given as

$W = F.d$

$W = Fdcos\theta$

here we know that

$\theta$ = angle between force and displacement

now we know that tension in the string and displacement of the object is always perpendicular to each other when the rock is twirled in circular path.

so we can say for this motion of the stone

$cos\theta = 0$

so work done by tension force on the twirled stone must be ZERO always

6 0

3 years ago

a rugby player passes the ball 5.34 m across the field, where it is caught at the same height as it left his hand. at what angle

MakcuM [25]

Answer:

$31.035^{\circ}$

Explanation:

x = Displacement in x direction = 5.34 m

t = Time taken to travel the displacement

y = Displacement in y direction = 0

u = Initial velocity of ball = 7.7 m/s

g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

Displacement in x direction is given by

$x=u\cos\theta t\\\Rightarrow t=\dfrac{5.34}{7.7 \cos\theta}$

Displacement in y direction is given by

$y=u\sin\theta t-\dfrac{1}{2}gt^2\\\Rightarrow 0=7.7\sin\theta \dfrac{5.34}{7.7\cos\theta}-\dfrac{1}{2}\times 9.81 (\dfrac{5.34}{7.7\cos\theta})^2\\\Rightarrow 0=7.7\sin\theta-4.905\times \dfrac{5.34}{7.7\cos\theta}\\\Rightarrow 0=7.7^2\sin\theta \cos\theta-4.905\times 5.34\\\Rightarrow 0=7.7^2\dfrac{\sin2\theta}{2}-4.905\times 5.34\\\Rightarrow 0=7.7^2\sin2\theta-4.905\times5.34\times 2\\\Rightarrow \sin2\theta=\dfrac{4.905\times 5.34\times 2}{7.7^2}\\\Rightarrow 2\theta=\sin^{-1}\dfrac{4.905\times 5.34\times 2}{7.7^2}$

$\Rightarrow \theta=\dfrac{62.07}{2}\\\Rightarrow \theta=31.035^{\circ}$

The angle at which the ball was thrown is $31.035^{\circ}$ .

7 0

3 years ago

Water is most dense at 4 degrees Celsius. Since at this temperature 1 ml of water has a mass of 1 g. What is its density?

sveticcg [70]

The density is 1. 1/1=1

7 0

3 years ago

Read 2 more answers

Please help me .finish this paper​

Please help me .finish this paper