Question

The unit of current, the ampere, is defined in terms of the force between currents. Two 1.0-meter-long sections of very long wires a distance 1.5 m apart each carry a current of 1.0 A.
Required:
What is the force between them

Answer 1

Answer:

$1.33\times 10^{-8} N$

Explanation:

According to the given scenario, the computation of force between them is shown below:-

As we know that

$\mu = 4\pi\times 10^{-7}$

The force between two current carrying wires will be

$F = \frac{\mu_oI_1I_2L}{2\pi r}$

$= \frac{4\pi\times 10^{-7} (1 A) (1 A) (1.0 m)}{2\pi (1.5m)}$

$= 1.33\times 10^{-7} N$

$= 1.33\times 10^{-8} N$

Therefore for computing the force between two wires we simply applied the above formula.

So, the force between two wires carrying 1 A current $= 1.33\times 10^{-8} N$.