The type of friction of a kite suspended
in the sky that is flowing back and forth is fluid friction. The fluid here is
the air that helps the kite move back and forth. The kite feels a drag force
due to air which acts in the upward direction.
Answer:
Explanation:
For this problem we must use Newton's second law where force is gravitational attraction
F = m a
Since movement is circular, acceleration is centripetal.
a = v2 / r
Let's replace
G m M / r² = m v² / r
G M r = v²
The distance r is from the center of the planet
r = R + h
v = √ GM / (R + h)
If the friction force is not negligible
F - fr = m a
Where the friction force must have some functional relationship, for example
Fr = b v + c v² +…
Suppose we are high enough for the linear term to derive the force of friction
G m M / r - (m b v + m c v2) = m v2
G M / r - b v = v²
We see that the solution of the problem gives lower speeds and that change over time.
To compensate for this friction force, the motors should be intermittently suspended to recover speed.
Answer: no
Explanation: we need a picture
Answer:
+5300 kg m/s
Explanation:
In any type of collision, the total momentum is conserved. Therefore, we can just calculate the total momentum before the collision, and the final momentum will be equal to the initial one.
The total momentum before the collision is:
where
is the mass of the bus
is the mass of the car
is the initial velocity of the bus
is the initial velocity of the car
Substituting the numbers, we find
And since the total momentum is conserved, this is also the final momentum after the collision.
