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3 years ago

12

a machine gun fires 10 rounds per second the speed of the bullets is 300 m/s. what is the distance in the air between the flying

bullets ?

1 answer:

vovangra [49]3 years ago

4 0

<span>(300 m/s)/(10 r/s) = 30 m/round.</span>

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Prove: <br>1) p=dhg <br>.........<br>

Lilit [14]

Explanation:

P = F/A

P = mg/A [ since F = mg ]

P = Vdg/A [ since m = Vd ]

P = Ahdg/A [ since V = Ah ]

P = hdg

6 0

2 years ago

Farah claps his 600times in 60seconds. what is the friquency and periodb

rosijanka [135]

Answer:

$\huge\boxed{\sf Frequency = 10\ Hz}$

$\huge\boxed{\sf Time\ Period = 0.1\ secs}$

Explanation:

<u>Given:</u>

No. of times = 600 times

Time = 60 seconds

<u>Required:</u>

Frequency = f = ?

Time Period = T = ?

<u>Solution:</u>

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5 0

3 years ago

A proton moves perpendicular to a uniform magnetic field B at a speed of 2.30 107 m/s and experiences an acceleration of 2.50 10

Katen [24]

Answer:

B = 6.18 10⁻⁶ T

the magnetic field is in the negative direction of the y axis

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The magnetic force is given by

F = q v x B

as in the exercise indicate that the velocities perpendicular to the magnetic field,

F = q v B

Newton's second law is

F = m a

let's substitute

q v B = m a

B = m a / q v

let's calculate

B = 9.1 10⁻³¹ 2.50 10¹³ / (1.6 10⁻¹⁹ 2.30 10⁷)

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The direction of the field can be obtained with the right hand rule, where the thumb points in the direction of the velocity, the fingers extended in the direction of the magnetic field and the palm in the direction of the force for a positive charge.

In the exercise indicate that the velocity is the z axis

the acceleration and therefore the force in the x axis

therefore the magnetic field is in the negative direction of the y axis

7 0

2 years ago

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evablogger [386]

The answer is (a) hope it helped!<3

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2 years ago

For your senior project, you are designing a Geiger tube for detecting radiation in the nuclear physics laboratory. This instrum

Paha777 [63]

Answer:

Maximum linear charge density = 84.14 nC/m

Explanation:

Looking at this question, The electric field of a line charge of infinite length is given by : Er = (1/(2πεo)) x (λ/r)

r = the distance from the center of the line of charge

λ = the linear charge density of the wire.

Now looking at the equatiom, due to the fact that Er varies inveresely with r, its maximum value will occur at the surface of the wire where r = R, the radius of the wire:

And so, Emax = (1/(2πεo)) x (λ/R)

Let's make λ the subject of the equation and we get;

λ = 2πεo(REmax)

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Also, Emax = 5.50 × 10^(6) N/C

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Plugging these values into the equation, we get;

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3 years ago