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3 years ago

Young's Modulus refers to changes in the a Volume b- Length c- Body layers

Physics

1 answer:

Novosadov [1.4K]3 years ago

8 0

Explanation:

Young' modulus is the ratio of normal stress to the longitudinal strain. Mathematically, it is given by :

Normal stress is given by force per unit area. Longitudinal strain is the change in length per unit original length.

The mathematical definition of Young's modulus is given by :

$Y=\dfrac{F/A}{\Delta L/L}$ ..........(1)

Where

$\Delta L$ is the change in length

F is the force

A is the area of cross section

So, the Young's modulus refers to the change in length of the object. Hence, the correct option is (b) "length".

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Describe how electricity flows through a simple closed circuit.

Vedmedyk [2.9K]

Answer:

Electrons are drawn from one end of the battery to the other. Connecting two of those ends allows an electric current to flow between them. Wires make a path through that current can flow from one end of a battery to the other end, which would be considered as: The north and east side

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3 years ago

What determines an object’s thermal energy

Tems11 [23]

Answer:

temperature and mass

Explanation:

The higher the temperature of a given quantity of a substance, more is its thermal energy.

If a substance contains more mass, this also implies that the object has more particles in it . hence, it has high thermal energy.

Additional Information :

Temperature is a measure of the average kinetic energy of the particles of a substance.

The thermal energy of an object depends on three factors:

number of molecules in the object
temperature of the object.
thermal energy it has.

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3 years ago

Two solid balls (one larger, the other small) and a cylinder roll down a hill. Which has the greatest speed at the bottom and wh

makvit [3.9K]

The answer is c hope this clarifies

6 0

3 years ago

A spring of constant 20 N/m has compressed a distance 8 m by a(n) 0.3 kg mass, then released. It skids over a frictional surface

Fiesta28 [93]

Answer:

$X_2=25.27m$

Explanation:

Here we will call:

1. $E_1$ : The energy when the first spring is compress

2. $E_2$ : The energy after the mass is liberated by the spring

3. $E_3$ : The energy before the second string catch the mass

4. $E_4$ : The energy when the second sping compressed

so, the law of the conservations of energy says that:

1. $E_1 = E_2$

2. $E_2 -E_3= W_f$

3. $E_3 = E_4$

where $W_f$ is the work of the friction.

1. equation 1 is equal to:

$\frac{1}{2}Kx^2 = \frac{1}{2}MV_2^2$

where K is the constant of the spring, x is the distance compressed, M is the mass and $V_2$ the velocity, so:

$\frac{1}{2}(20)(8)^2 = \frac{1}{2}(0.3)V_2^2$

Solving for velocity, we get:

$V_2$ = 65.319 m/s

2. Now, equation 2 is equal to:

$\frac{1}{2}MV_2^2-\frac{1}{2}MV_3^2 = U_kNd$

where M is the mass, $V_2$ the velocity in the situation 2, $V_3$ is the velocity in the situation 3, $U_k$ is the coefficient of the friction, N the normal force and d the distance, so:

$\frac{1}{2}(0.3)(65.319)^2-\frac{1}{2}(0.3)V_3^2 = (0.16)(0.3*9.8)(2)$

Volving for $V_3$ , we get:

$V_3 = 65.27 m/s$

3. Finally, equation 3 is equal to:

$\frac{1}{2}MV_3^2 = \frac{1}{2}K_2X_2^2$

where $K_2$ is the constant of the second spring and $X_2$ is the compress of the second spring, so:

$\frac{1}{2}(0.3)(65.27)^2 = \frac{1}{2}(2)X_2^2$

solving for $X_2$ , we get:

$X_2=25.27m$

3 0

3 years ago

The angular separation of two stars is 0.1 arcseconds and you photograph them with a telescope that has an angular resolution of

gizmo_the_mogwai [7]

Answer:

Will see them as only one star

Explanation:

Solution:

- The angular resolution of a telescope means the minimum quantity that can be visualized. Since their angular separation ( 0.1 arcseconds ) is smaller than the telescope's angular resolution (1 arcseconds ), your photograph will seem to show only one star rather than two.

7 0

3 years ago