Answer:
The concentration of the solution will be much lower than 6M
Explanation:
To prepare a solution of a solid, the appropriate mass is taken and accurately weighed in a weighing balance and then made up to mark with distilled water.
From
n= CV
n = number of moles m/M( m= mass of solid, M= molar mass of compound)
C= concentration of substance
V= volume of solution
m=120g
M= 40gmol-1
V=500ml
120/40= C×500/1000
C= 120/40× 1000/500
C=6M
This solution will not be exactly 6M if the student follows the procedure outlined in the question. The actual concentration will be much less than 6M.
This is because, solutions are prepared in a standard volumetric flask. Using a 1000ml beaker, the student must have added more water than the required 500ml thereby making the actual concentration of the solution less than the expected 6M.
The freezing point of a solution containing 5. 0 grams of KCl and 550.0 grams of water is - 0.45°C
Using the equation,
Δ = im
where:
Δ = change in freezing point (unknown)
i = Van't Hoff factor
= freezing point depression constant
m = molal concentration of the solution
Molality is expressed as the number of moles of the solute per kilogram of the solvent.
Molal concentration is as follows;
MM KCl = 74.55 g/mol
molal concentration =
molal concentration = 0.1219m
Now, putting in the values to the equtaion Δ = im we get,
Δ = 2 × 1.86 × 0.1219
Δ = 0.4536°C
So, Δ of solution is,
Δ = 0.00°C - 0.45°C
Δ = - 0.45°C
Therefore,freezing point of a solution containing 5. 0 grams of KCl and 550.0 grams of water is - 0.45°C
Learn more about freezing point here;
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<h3>
Answer:</h3>
The gas obeys the Boyle's law
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Explanation:</h3>
- According to Boyle's law, the volume of a fixed mass of a gas and the pressure are inversely proportional at constant absolute temperature.
- That is;
- Therefore, , where k is a constant
- At varying volume and pressures while keeping absolute temperature constant; k = P1V1 =P2V2
In this case, we are given;
Initial Volume of 13.0 L at initial pressure of 1.0 atm
New volume of 6.5 L at new pressure of 2.0 atm
But, K = PV
Therefore,
k1 = P1V1
= 1.0 atm × 13.0 L
= 13 atm.L
k2 = P2V2
= 2.0 atm × 6.5 L
= 13 atm.L
Thus, k1=k2
Thus, the gas obeys the Boyle's law
Both are caused by human ignorance. Both have the ability to kill those in them. Both can become compact to create new material.
Answer: Ti is the reducing agent because it changes from 0 to +4 oxidation state.
Explanation:
- Firstly, we need to identify the reducing agent and the oxidizing agent.
- The reducing agent: is the agent that has been oxidized via losing electrons.
- The oxidizing agent: is the agent that has been reduced via gaining electrons.
- Here, Ti losses 4 electrons and its oxidation state is changed from 0 to +4 and Cl₂ gains one electron and its oxidation state is changed from 0 to -1.
- So, Ti is the reducing agent because its oxidation state changes from 0 to +4.
- Cl₂ is the oxidizing agent because its oxidation state changes from 0 to -1.
- Thus, The right answer is Ti is the reducing agent because it changes from 0 to +4 oxidation state.