Answer: Option (a) is the correct answer.
Explanation:
The given data is as follows.
= 4.19 
= 1.9
Heat of vaporization (
) at 1 atm and 
is 2259 kJ/kg
= 0
Therefore, calculate the enthalpy of water vapor at 1 atm and as follows.
= +
= 0 + 2259 kJ/kg
= 2259 kJ/kg
As the desired temperature is given 
and effect of pressure is not considered. Hence, enthalpy of liquid water at 10 bar and is calculated as follows.
= 
= 334.781 kJ/kg
Hence, enthalpy of water vapor at 10 bar and is calculated as follows.
= 
= 2410.81 kJ/kg
Therefore, calculate the latent heat of vaporization at 10 bar and as follows.
= 
= 2410.81 kJ/kg - 334.781 kJ/kg
= 2076.029 kJ/kg
or, = 2076 kJ/kg
Thus, we can conclude that at 10 bar and latent heat of vaporization is 2076 kJ/kg.
Answer:
i dont have a answer im just answering so you can give the person who answered brailiest :)
Explanation:
Answer:
Fnet = 20 Newton
Explanation:
Let the force applied by Brian be Fb.
Let the force applied by Alice be Fa.
<u>Given the following data;</u>
Force, Fb = 10N
Force, Fa = 30N
To find the net force, Fnet;
Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.
Mathematically, net force is given by the formula;
Where;
- Fapp is the applied force
- Fg is the force due to gravitation
Since the two force applied to the box are acting in opposite direction, we would subtract their values to find the net force.
Fnet = Fa - Fb
Fnet = 30 - 10
Fnet = 20 Newton
Answer:
1.17 grams
Explanation:
Let's consider the balanced equation for the combustion of ethylene.
C₂H₄(g) + 3 O₂(g) → 2 CO₂(g) + 2 H₂O(l)
We can establish the following relations:
- 1411 kJ are released (-1411 kJ) when 1 mole of C₂H₄ burns.
- The molar mass of C₂H₄ is 28.05 g/mol.
The grams of C₂H₄ burned to give 59.0 kJ of heat (q = -59.0 kJ) is:
