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2 years ago

The most valuable part of the carcass is the

Chemistry

1 answer:

harkovskaia [24]2 years ago

8 0

Answer:

The rib and loin, because of their palatability and diversity in how they can be used--especially on the market.

Explanation:

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Never mind, question solved.

Alchen [17]

The answer to the problem is 100

5 0

1 year ago

I have 2 samples of solid chalk (aka calcium carbonate). Sample A has a total mass of 4.12 g and Sample B has a total mass of 19

IRINA_888 [86]

Answer:

A) Sample B has more calcium carbonate molecules

Explanation:

M = Molar mass of calcium carbonate = 100.0869 g/mol

$N_A$ = Avogadro's number = $6.022\times 10^{23}\ \text{mol}^{-1}$

For the 4.12 g sample

Moles of a substance is given by

$n=\dfrac{m}{M}\\\Rightarrow n=\dfrac{4.12}{100.0869}\\\Rightarrow n=0.0411\ \text{mol}$

Number of molecules is given by

$nN_A=0.0411\times 6.022\times 10^{23}=2.48\times 10^{22}\ \text{molecules}$

For the 19.37 g sample

$n=\dfrac{19.37}{100.0869}\\\Rightarrow n=0.193\ \text{mol}$

Number of molecules is given by

$nN_A=0.193\times 6.022\times 10^{23}=1.16\times 10^{23}\ \text{molecules}$

$1.16\times 10^{23}\ \text{molecules}>2.48\times 10^{22}\ \text{molecules}$

So, sample B has more calcium carbonate molecules.

The ratio of the elements of carbon, oxygen, calcium atoms, ions, has to be same in both the samples otherwise the samples cannot be considered as calcium carbonate. Same is applicable for impurities. If there are impurites then the sample cannot be considered as calcium carbonate.

7 0

2 years ago

How would you seprate a mixture of sand and salt?

lys-0071 [83]

First, you mix the salt and sand with water, so the salt dissolves. Next, you filter the sand out, so you have the slat water and sand separated. Then, you evaporate the water, leaving the salt behind.

3 0

2 years ago

Read 2 more answers

What is the chemical test for chlorine?

Ann [662]

Answer:

hope it helps you a little

3 0

2 years ago

What does the pKa of the conjugate acid of a base have to be to remove a hydrogen from water (pKa = 15.7) so that the ratio of h

Inga [223]

Answer:

The pKa of the conjugate acid is 17.7

Explanation:

If hydrogen is removed from water, the equilibrium concentration of the conjugate acid according to the information given in the question becomes,

Kₐ = [OH⁻]/[H₂O]

$K_a=\frac{100}{1} =100$

Now, we determine the equivalent pKa

pKa = -log[ka]

pKa = -log[100]

pKa = -2

Removal of hydrogen from water is reversible as shown below;

H₂O ⇄ OH⁻ + H⁺

15.7 -2

This reaction is reversible, and the difference in pKa = pKa[H₂O] - pKa[H⁺];

pKa of the conjugate acid = 15.7 - (-2) = 17.7

The pKa of the conjugate acid is 17.7

5 0

3 years ago